java - 如何从android应用程序设置参数到服务器？

我有以下代码从我的android应用程序连接到zappos api服务器并搜索一些东西。但是它要么返回error 404 or We are unable to process the request from the input feilds given。

当我执行相同的查询时，它可以在Web浏览器上运行。

查询是：

http://api.zappos.com/Search&term=boots&key=<my_key_inserted_here>

码：

HttpClient client = new DefaultHttpClient();
HttpPost post = new HttpPost("http://api.zappos.com/Search");

NameValuePair keypair = new BasicNameValuePair("key",KEY);
NameValuePair termpair = new BasicNameValuePair("term",data);

List<NameValuePair> params = new ArrayList<NameValuePair>(2);

params.add(keypair);
params.add(termpair);

post.setEntity(new UrlEncodedFormEntity(params));
HttpResponse response = client.execute(post);

String str;
StringBuilder sb = new StringBuilder();
HttpEntity entity =response.getEntity();
if (entity != null) {
    DataInputStream in = new DataInputStream(entity.getContent());
    while (( str = in.readLine()) != null){
        sb.append(str);
    }

    in.close();
}

Log.i("serverInterface","response from server is :"+sb.toString());

我究竟做错了什么？

最佳答案

如果我是正确的话，您想要做的是带有参数的GET请求。

然后，代码看起来像这样：

    HttpClient client = new DefaultHttpClient();
    HttpGet get = new HttpGet("http://api.zappos.com/Search");

    HttpParams params = new BasicHttpParams();
    params.setParameter("key", "KEY");
    params.setParameter("term", "data");
    get.setParams(params);

    HttpResponse response;
    response = client.execute(get);

    String str;
    StringBuilder sb = new StringBuilder();
    HttpEntity entity = response.getEntity();
    if (entity != null) {
        DataInputStream in;
        in = new DataInputStream(entity.getContent());
        while ((str = in.readLine()) != null) {
            sb.append(str);
        }
        in.close();
    }

    Log.i("serverInterface", "response from server is :" + sb.toString());