您好,我正在尝试更改如何在不更改名称的情况下访问数据库列名,例如,我的列名是resourceType
,但我想将其命名,而且我希望响应json出现name
,而不是resourceType
。环顾互联网发现我应该使用protected $maps = ['oldName' => 'newName'];
但不起作用。我想更改resourceType
,因为我认为表名不应该等于列resourceType->resourceType
这是我的模型
<?php
namespace Knotion;
use Illuminate\Database\Eloquent\Model;
use Mappable, Mutable;
class CTL_ResourceType extends Model {
public $timestamps = false;
protected $table = "CTL_ResourceType";
protected $primaryKey = "idResourceType";
public $incrementing = false;
public static $snakeAttributes = false;
protected $hidden = ['idCountry', 'idCompany', 'initials', 'thumbnail', 'icon', 'status', 'createTime', 'updateTime'];
protected $fillable = ['name'];
protected $maps = ['resourceType' => 'name'];
protected $appends = ['name'];
public function resource() {
return $this->hasMany('Knotion\CTL_Resource', 'idResource' );
}
public function country() {
return $this->belongsTo('Knotion\CTL_Country', 'idCountry', 'idCountry');
}
public function company() {
return $this->belongsTo('Knotion\CTL_Company', 'idCompany', 'idCompany');
}
}
这是我收到的json响应。如你所见,这里仍然是
resourceType
{
"total": 16,
"per_page": 15,
"current_page": 1,
"last_page": 2,
"next_page_url": "http://localhost:8000/krb/api/resources?page=2",
"prev_page_url": null,
"from": 1,
"to": 15,
"data": [
{
"idResource": "4e8f1ece-f666-11e5-8137-0f7932903a75",
"productionKey": "238493ujjsl",
"title": "ElTitle16",
"description": "ElDescription16",
"minimumAge": "4",
"maximumAge": "15",
"fileName": "ElFileName16",
"extension": ".png",
"URL": "ElURL16",
"createTime": "2016-03-30 04:58:16",
"creatorUser": {
"idUser": "85cf125c-f5ff-11e5-8137-0f7932903a75",
"name": "Roberto"
},
"creationCountry": {
"idCountry": "f03a75a0-f5ff-11e5-8137-0f7932903a75",
"country": "Estados Unidos"
},
"resourceType": {
"idResourceType": "5c902028-f601-11e5-8137-0f7932903a75",
"resourceType": "TípodeRecurso3"
},
"tags": [
{
"idTag": "40c6a114-f520-11e5-8137-0f7932903a75",
"name": "ElTag1"
}
],
"quickTags": [
{
"idQuickTag": "679bc8f0-f520-11e5-8137-0f7932903a75",
"name": "ElQuickTag4"
}
],
"relatedTo": [
{
"idRelatedTo": "7beddc6c-f520-11e5-8137-0f7932903a75",
"name": "ElRelatedTo3"
}
]
}
最佳答案
我以前没有听说过$maps
属性或Mappable
,所以我做了一个快速搜索。看起来它们(以及Mutable
)是jarektkaczyk/eloquence包的一部分。
在这种情况下,Mappable
和Mutable
都是应该添加到类中的特征。此外,为了让它们正常工作,还需要添加Eloquence
特性。
需要更改文件顶部的use
语句,以便在正确的命名空间中正确地寻址类名,然后需要将特征添加到类中:
<?php
namespace Knotion;
// import the class names
use Sofa\Eloquence\Mutable;
use Sofa\Eloquence\Mappable;
use Sofa\Eloquence\Eloquence;
use Illuminate\Database\Eloquent\Model;
class CTL_ResourceType extends Model {
// add the traits to the class
use Eloquence, Mappable, Mutable;
// code...
}
编辑
如果你想在没有软件包的情况下完成这项工作,你需要做三件事:
您需要将
resourceType
添加到$hidden
数组中,这样它就不会出现在toArray()
/toJson()
结果中。protected $hidden = ['idCountry', 'idCompany', 'initials', 'thumbnail', 'icon', 'status', 'createTime', 'updateTime', 'resourceType'];
您需要创建一个
getNameAttribute()
accessor method,当您试图访问name
属性时,将调用该属性。public function getNameAttribute() {
return $this->resourceType;
}
您需要将
name
添加到$appends
数组中,以便它包含在toArray()
/toJson()
结果中。protected $appends = ['name'];
或者,如果这感觉工作量太大,您可以重写
toArray()
方法(由toJson()
调用)来强制您的命名约定,以及:public function toArray() {
// call parent method to get initial array results
$array = parent::toArray();
// set the new key with data
$array['name'] = $array['resourceType'];
// unset the old key
unset($array['resourceType']);
// return the array
return $array;
}
关于php - Laravel 5.2更改数据库列名称引用,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/36324086/