java - 将分钟转换成人类可读的格式

快速提问。

是否有更聪明/更时尚的方式将分钟转换为更易读的格式，仅显示最高有效数字？

我正在使用Android Studio的Java。

public String MinutesToHumanReadable(Long minutes) {

...

}

即

2 mins = "2 mins"
45 mins = "45 mins"
60 mins = ">1 hr"
85 mins = ">1 hr"
120 mins = ">2 hrs"
200 mins = ">3 hrs"
1500 mins = ">1 day"

我的代码非常繁琐，草率，并且有些难以理解。

public String MinutesToHumanReadable(long minutes) {
    String sReturn = "";

    if (minutes > 515600) {
        sReturn = "> 1 yr";

    } else if (minutes > 43200) {
        sReturn = (minutes / 43200) + " mths";

    } else if (minutes > 10080) {
        sReturn = (minutes / 10080) + " wks";

    } else if (minutes > 1440) {
        sReturn = (minutes / 1440) + " days";

    } else if (minutes > 60) {
        sReturn = (minutes / 60) + " hrs";

    } else {
        //<60
        sReturn = minutes + " mins";

    }

    return sReturn;
}

非常感谢，
Ĵ

最佳答案

好吧，有可能，我想出了，我为此感到骄傲! :)
请注意，仅通过更改这两个数组中的值，就可以轻松添加任何其他值而无需更改方法本身。例如，如果“年”不足以满足您的需求，则可以添加“十年”和“百年” ...

如果您的输出值超过1，则此代码还将在末尾添加“s”字母。

public class SuperMinutesChangerClass {
    public static int[] barriers = {1, 60, 60*24, 60*24*7, 60*24*365, Integer.MAX_VALUE};
    public static String[] text = {"min", "hr", "day", "week", "year"};

    public static String minutesToHumanReadable(int minutes){
        String toReturn = "";
        for (int i = 1; i < barriers.length; i++) {
            if (minutes < barriers[i]){
                int ammount = (minutes/barriers[i-1]);
                toReturn = ">" + (ammount) + " " + text[i-1];
                if (ammount > 1){
                    toReturn += "s";
                }
                break;
            }
        }
        return toReturn;
    }
}

样本输入:

    public static void main(String[] args) {
        System.out.println(minutesToHumanReadable(10));
        System.out.println(minutesToHumanReadable(60));
        System.out.println(minutesToHumanReadable(61));
        System.out.println(minutesToHumanReadable(121));
        System.out.println(minutesToHumanReadable(8887));
        System.out.println(minutesToHumanReadable(9999743));
    }

输出为:

>10 mins
>1 hr
>1 hr
>2 hrs
>6 days
>19 years