python - 最明确定义var时的Python NameError

def make_pdf(self):
        self.get_filez()
        self.get_client()
        file_name = self.client_id+"_"+self.client_name+"_"+self.batch_num
        style = libxslt.parseStylesheetDoc(self.xsl_file)
        transformation = style.applyStylesheet(self.xml_file,None)
        style.saveResultToFilename("tmp/"+file_name+".fo",transformation,0)
        style.freeStylesheet()
        self.xml_file.freeDoc()
        transformation.freeDoc()
        fop_cmd = "/usr/bin/xmlgraphics-fop"
        #file_name = self.tpa+"_"+self.be+"_"+self.batch_num
        cmd = [fop_cmd,"-fo","tmp/"+file_name+".fo","-pdf","tmp/"+file_name+".pdf"]
        #fop_transform = subprocess.Popen(cmd,stdout=subprocess.PIPE,stderr=subprocess.STDOUT)
        #fop_log = "-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-\n"
        #fop_log = fop_log + time.strftime('%Y-%m-%d %R:%S')+"\n"
        #fop_log = fop_log + file_name+".fo" + "\n"
        #fop_log =  fop_transform.communicate()[0]+"\n"
        #f = open("/tmp/error_log","a")
        #f.write(fop_log)
        #f.close()

确定如果我注释掉cmd变量声明，代码将运行并正确创建fo文件。与上面一样，它没有注释，我在未定义的file_name上得到NameError（位于顶部）。如果我取消注释在cmd声明上方的第二个file_name声明，它将在自身上引发NameError。 '。'在过去，当发生这种情况时，这是一种语法错误。我想念它，请帮助！

当file_name的第二个声明被注释掉时：

Traceback (most recent call last):
  File "make_pdfs.py", line 11, in ?
    from MakePdfs import MakePdfs
  File "/home/khouser/removed/removed/MakePdfs.py", line 16, in ?
    class MakePdfs:
  File "/home/khouser/removed/removed/MakePdfs.py", line 39, in MakePdfs
    cmd = [fop_cmd,"-fo","tmp/"+file_name+".fo","-pdf","tmp/"+file_name+".pdf"]
NameError: name 'file_name' is not defined

当第二个file_name声明未注释时：

Traceback (most recent call last):
  File "make_pdfs.py", line 11, in ?
    from MakePdfs import MakePdfs
  File "/home/khouser/removed/removed/MakePdfs.py", line 16, in ?
    class MakePdfs:
  File "/home/khouser/removed/removed/MakePdfs.py", line 38, in MakePdfs
    file_name = self.tpa+"_"+self.be+"_"+self.batch_num
NameError: name 'self' is not defined

最佳答案

您的文件包含不可见的控制字符可能会引起神秘的NameErrors。在UNIX机器上，您可以通过查看以下命令的输出来发现这些错误：

cat -A filename.py

关于python - 最明确定义var时的Python NameError，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/5756777/