我正在做一个作业，其中我必须实例化几个不同的对象并在屏幕上格式化它们。我无法正确输出字符串；代替文本，我得到这样的输出
run:
First Name Last Name Student ID Number
studentdemo.StudentDemo@6d06d69c
studentdemo.StudentDemo@7852e922
studentdemo.StudentDemo@4e25154f
studentdemo.StudentDemo@70dea4e
studentdemo.StudentDemo@5c647e05
BUILD SUCCESSFUL (total time: 0 seconds)
这是我的主要
package studentdemo;
public class MainStudent {public static void main(String[] args) {
StudentDemo student1 = new StudentDemo("Peter\t","Adams\t","123546\t");
StudentDemo student2 = new StudentDemo("James\t","Clark\t","654332\t");
StudentDemo student3 = new
StudentDemo("Christopher\t","Colombo\t","223344\t");
StudentDemo student4 = new StudentDemo("Amy\t","Tan\t","997766\t");
StudentDemo student5 = new
StudentDemo("Marry\t","Madison\t","6543321\t");
System.out.println("First Name\t"+"Last Name\t"+"Student ID Number\t");
System.out.println(student1);
System.out.println(student2);
System.out.println(student3);
System.out.println(student4);
System.out.println(student5);
}
}
这是我的另一堂课
package studentdemo;
public class StudentDemo {
private String firstName;
private String lastName;
private String studentIdNumber;
public StudentDemo(String firstName, String lastName, String
studentIdNumber) {
this.firstName = firstName;
this.lastName = lastName;
this.studentIdNumber = studentIdNumber;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getFirstName() {
return firstName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
public String getLastName() {
return lastName;
}
public void setStudentIdNubmer(String studentIdNumber) {
this.studentIdNumber = studentIdNumber;
}
public String getStudentIdNumber() {
return studentIdNumber;
}
}
我做错了什么？
最佳答案
这是因为您尝试打印对象（student1）而不是对象的属性。
请试试：
System.out.println（student1.getFirstName（）+“ \ t” + student1.getLastName（）+“ \ t” + student1.getStudentIdNumber（））;
代替：
System.out.println(student1);
希望这能解决您的问题。