我有一个动态的对象数组,它取决于表中行的选择。一个例子:
var obj = [
{ name: "test1", totalCosts: 45560, actualTotalCosts: 652112, riskCosts: 65442 },
{ name: "test2", totalCosts: 3434, actualTotalCosts: 25252, riskCosts: 34234 },
{ name: "test3", totalCosts: 23123, actualTotalCosts: 23242, riskCosts: 0 },
];
生成此数组后,我想调用一个函数,该函数将在此数组中再推一行并将其命名为“ total”,并对所有受尊敬的值进行求和,如下所示:
{name:“ total”,totalCosts:72117,actualTotalCosts:700606,riskCosts:99676}
obj [0] .totalCosts + obj [1] .totalCosts + obj [2] .totalCosts = obj [3] .totalCosts
我尝试用有限的知识编写一个,但是该函数不是将所有三个对象的值求和,而是将整个对象求和成一个。
function sum1( obj ) {
var result1 = [];
for (var i = 0; i < obj.length; i++) {
var sum = 0, arr = [];
for (var key in obj[i]) {
if (key != 'name') {
sum += obj[i][key];
arr.push(sum[key]);
}
}
result1.push(arr);
return result1;
}
}
请提供一个函数,该函数可以对所有对象求和并返回带有总数的数组。我也尝试使用d3.sum,但未成功。
最佳答案
您可以借助d3.sum采取功能性方法。
obj.push(d3.keys(obj[0]) //get the keys from obj[0]
.reduce(function(sumRow, sumCol) { //construct a summary row
var isNum = !isNaN(obj[0][sumCol]) //only sum numeric fields
return (sumRow[sumCol] = (isNum ? d3.sum(obj, function(row) {
return row[sumCol] //accessor for the column for d3.sum
}) : "All"), sumRow) //append the sum col to the sum row object
},{})); //initial value for reduce is {}
工作实例
(function() {
var obj = [{
name: "test1",
name2: "type1",
totalCosts: 45560,
actualTotalCosts: 652112,
riskCosts: 65442
}, {
name: "test2",
name2: "type2",
totalCosts: 3434,
actualTotalCosts: 25252,
riskCosts: 34234
}, {
name: "test3",
name2: "type3",
totalCosts: 23123,
actualTotalCosts: 23242,
riskCosts: 0
}];
obj.push(d3.keys(obj[0])
.reduce(function(sumRow, sumCol) {
var isNum = !isNaN(obj[0][sumCol])
return (sumRow[sumCol] = (isNum ? d3.sum(obj, function(row) {
return row[sumCol]
}) : "All"), sumRow)
}, {}));
d3.select("#result").text(JSON.stringify(obj))
})()
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/3.4.11/d3.min.js"></script>
<div id="result"></div>