我有一个动态的对象数组,它取决于表中行的选择。一个例子:

var obj = [
            { name: "test1",  totalCosts: 45560, actualTotalCosts: 652112, riskCosts: 65442 },
            { name: "test2",  totalCosts: 3434,  actualTotalCosts: 25252,   riskCosts: 34234 },
            { name: "test3",  totalCosts: 23123, actualTotalCosts: 23242,  riskCosts: 0 },
        ];


生成此数组后,我想调用一个函数,该函数将在此数组中再推一行并将其命名为“ total”,并对所有受尊敬的值进行求和,如下所示:


  {name:“ total”,totalCosts:72117,actualTotalCosts:700606,riskCosts:99676}
  
  obj [0] .totalCosts + obj [1] .totalCosts + obj [2] .totalCosts = obj [3] .totalCosts


我尝试用有限的知识编写一个,但是该函数不是将所有三个对象的值求和,而是将整个对象求和成一个。

            function sum1( obj ) {
            var result1 = [];
            for (var i = 0; i < obj.length; i++) {
                var sum = 0, arr = [];
                for (var key in obj[i]) {
                    if (key != 'name') {
                        sum += obj[i][key];
                        arr.push(sum[key]);
                    }

                }
                result1.push(arr);
                return result1;
            }
        }


请提供一个函数,该函数可以对所有对象求和并返回带有总数的数组。我也尝试使用d3.sum,但未成功。

最佳答案

您可以借助d3.sum采取功能性方法。

  obj.push(d3.keys(obj[0])                //get the keys from obj[0]
    .reduce(function(sumRow, sumCol) {    //construct a summary row
      var isNum = !isNaN(obj[0][sumCol])  //only sum numeric fields
      return (sumRow[sumCol] = (isNum ? d3.sum(obj, function(row) {
        return row[sumCol]                //accessor for the column for  d3.sum
      }) : "All"), sumRow)                //append the sum col to the sum row object
    },{}));                               //initial value for reduce is {}




工作实例



  (function() {
    var obj = [{
      name: "test1",
      name2: "type1",
      totalCosts: 45560,
      actualTotalCosts: 652112,
      riskCosts: 65442
    }, {
      name: "test2",
      name2: "type2",
      totalCosts: 3434,
      actualTotalCosts: 25252,
      riskCosts: 34234
    }, {
      name: "test3",
      name2: "type3",
      totalCosts: 23123,
      actualTotalCosts: 23242,
      riskCosts: 0
    }];

    obj.push(d3.keys(obj[0])
      .reduce(function(sumRow, sumCol) {
        var isNum = !isNaN(obj[0][sumCol])
        return (sumRow[sumCol] = (isNum ? d3.sum(obj, function(row) {
          return row[sumCol]
        }) : "All"), sumRow)
      }, {}));

    d3.select("#result").text(JSON.stringify(obj))
  })()

<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/3.4.11/d3.min.js"></script>
<div id="result"></div>

08-03 17:05