我需要在rxcpp中实现一个摄像机采样系统。我以为这是将requestStream作为参数传递并接收responseStream的方式。

每次调用requestSample时,都会创建一个新的摄像头 session ,并且当对requestStream调用on_complete()时,摄像头 session 会终止

observable<ImageSample> requestSampleStream(observable<ImageRequest> requestStream$) {
  auto response$ = rxcpp::observable<>::create<ImageSample>(
  [&](rxcpp::subscriber<ImageSample> s){
    auto request_next = [&](ImageRequest imageRequest) {
      cout << "image request next" << endl;
      SampleImage vsi;
      s.on_next(vsi);
    };

    auto request_completed = [&] {
      cout << "no more samples needed.. close camera" << endl;
      s.on_completed();
    };

    auto request_error = [&](std::exception_ptr e) {
      try { rethrow_exception(e); }
      catch (const exception &ex) {
        cerr << "error happened on request stream.. close the camera and send error on return stream" << endl << ex.what() << endl;
      }

      s.on_error(e);
    };

    requestStream$.subscribe(request_next,
                              request_error,
                              request_completed
    );
  });

  return response$;
}

这里的问题是,在调用requestStream$.subscribe(request_next..时,我得到了EXC_BAD_ACCESS

最佳答案

s是本地堆栈变量,但是lambda捕获对s的引用。在调用lambda时,此引用无效。将[&]更改为[=],这应该可以工作!

另一种选择是使用现有的map算法。

observable<ImageSample> requestSampleStream(observable<ImageRequest> requestStream$) {
    return requestStream$ |
        map([](ImageRequest imageRequest){
            cout << "image request next" << endl;
            SampleImage vsi;
            s.on_next(vsi);
        })
        // optional
        | tap([&](std::exception_ptr e) {
            try { rethrow_exception(e); }
            catch (const exception &ex) {
                cerr << "error happened on request stream.. close the camera and send error on return stream" << endl << ex.what() << endl;
            }
        },
        [](){
            cout << "no more samples needed.. close camera" << endl;
        })
        ;
}

10-06 13:47