javascript - 如何有效地从geojson提取值？

我有以下结构的geojson文件：

var areas = {
"type": "FeatureCollection",
"features": [
{ "type": "Feature", "id": 0, "properties": { "name": "a", "count": "854" }, "geometry": { "type": "Polygon", "coordinates": [ [ [ 13.271687552328165, 29.359549285088008 ], [ 13.272222904657671, 29.357697459147403 ], [ 13.272586765837973, 29.35566049412985 ], [ 13.273062097784726, 29.354438105832578 ], [ 13.272652418199639, 29.360795108476978 ], [ 13.271320041078822, 29.360700647951568 ], [ 13.271687552328165, 29.359549285088008 ] ] ] } }
,
{ "type": "Feature", "id": 1, "properties": { "name": "b", "count": "254"}, "geometry": { "type": "Polygon", "coordinates": [ [ [ 13.277038163109875, 29.358442424220023 ], [ 13.276782949188294, 29.358122923383512 ], [ 13.275290999273452, 29.358508600578681 ], [ 13.274634727185679, 29.358485484466968 ], [ 13.282581930993208, 29.358635779719847 ], [ 13.278334024184868, 29.359814295404375 ], [ 13.277038163109875, 29.358442424220023 ] ] ] } }
,
{ "type": "Feature", "id": 2, "properties": {"name": "c", "count": "385"}, "geometry": { "type": "Polygon", "coordinates": [ [ [ 13.279484097462499, 29.349831113628788 ], [ 13.27792879702741, 29.349728966688758 ], [ 13.276089401418951, 29.349901260351807 ], [ 13.275677565886326, 29.349951087700632 ], [ 13.279484097462499, 29.349831113628788 ] ] ] } }
,
{ "type": "Feature", "id": 3, "properties": { "name": "d", "count": "243"}, "geometry": { "type": "Polygon", "coordinates": [ [ [ 13.290520299215724, 29.352306689134622 ], [ 13.289722088408338, 29.351802774685929 ], [ 13.289065241087885, 29.352101541350635 ], [ 13.28785814146197, 29.351114667998772 ],  [ 13.290520299215724, 29.352306689134622 ] ] ] } }

]
}

通常，要将这些数据转换为数组，我将创建一个循环以遍历将这个值存储在数组中的适当变量。但是，我不知道这是否是最好的方法。有没有一种方法可以将id的所有值提取到数组中，以便最终得到：

[0,1,2,3]

我很高兴使用任何外部库来执行此操作-我主要是想知道是否有比当前方法更有效的方法。

最佳答案

不是我的代码，但是这里有一篇关于从json高效获取值的文章。

参考帖子
use jQuery's find() on JSON object

用户Box9的回答可能是最好的方法

function getObjects(obj, key, val) {
    var objects = [];
    for (var i in obj) {
        if (!obj.hasOwnProperty(i)) continue;
        if (typeof obj[i] == 'object') {
            objects = objects.concat(getObjects(obj[i], key, val));
        } else if (i == key && obj[key] == val) {
            objects.push(obj);
        }
    }
    return objects;
}

也就此代码块提出了此答案，因为这是我发现的提取值的最佳方法