java - 我正在接收另一个对象的输出，这是错误的

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我的程序必须创建两个狗对象并为其赋予属性。在Dog类中，我必须有一个带有跳蚤的构造函数和一个不带跳蚤的构造函数。使用该程序时，我从输出之一中的错误对象接收到信息。

public class JavaProgram{
    public static void main (String [] args){
        Dog dog1 = new Dog ("Luca", "mutt", 'M', 22, 5 );
        Dog dog2 = new Dog ("test", "Golden Retriever", 'F', 12, 9, true );

        System.out.println("Dog1's name is " + dog1.getName() + ", its breed is " +
        dog1.getBreed() + ", its sex is " + dog1.getSex() + ", its age in months is " +
        dog1.getAge() + ", its weight in pounds is  " + dog1.getWeight());

        System.out.println("When Dog1 eats it makes the noise " + dog1.getEating() +
        ", and when its barks the noise made is " + dog1.getBarking());

        System.out.println("Dog2's name is " + dog1.getName() + ", its breed is " +
        dog2.getBreed() + ", its sex is " + dog2.getSex() + ", its age in months is " +
        dog2.getAge() + ", its weight in pounds is  " + dog2.getWeight());

        System.out.println("When Dog2 eats it makes the noise " + dog2.getEating() +
        ", and when its barks the noise made is " + dog2.getBarking() + "It does" + dog2.getFleas());
    }
}

public class Dog{

    private String name;
    private String breed;
    private char sex;
    //In months
    private int age;
    //In pounds
    private double weight;
    private boolean fleas;
    private String yesFleas;
    private String noFleas;
    private String eating;
    private String barking;


    public Dog(String name, String breed, char sex, int age, double weight){
        this("Chomp, chomp, chomp", "Woof, woof, woof");
        this.name = name;
        this.breed = breed;
        this.sex = sex;
        this.age = age;
        this.weight = weight;
    }
    public Dog(String name, String breed, char sex, int age, double weight, boolean fleas){
        this( "Chomp, chomp, chomp", "Woof, woof, woof", "have fleas, scratch, scratch, scratch", "not have fleas, yay!");
        this.name = name;
        this.breed = breed;
        this.sex = sex;
        this.age = age;
        this.weight = weight;
        this.fleas = fleas;
    }

    public Dog(String eating, String barking){
        this.eating = eating;
        this.barking = barking;
    }

    public Dog(String eating, String barking, String yesFleas, String noFleas){
        this.eating = eating;
        this.barking = barking;
        this.yesFleas = yesFleas;
        this.noFleas = noFleas;
    }

    public String getName(){
        return name;
    }

    public String getBreed(){
        return breed;
    }

    public char getSex(){
        return sex;
    }

    public int getAge(){
        return age;
    }

    public double getWeight(){
        return weight;
    }


    public String getEating(){
        return eating;
    }

    public String getBarking(){
        return barking;
    }
    public String getFleas(){

        if (fleas == true)
            return yesFleas;
        else
            return noFleas;

    }
}

我应该得到“ Dog2的名字是test，它的品种是金毛，它的性别是F，它的月龄是12，它的体重（磅）是9.0”，但是我得到Dog2的名字是Luca，它的品种是Golden Retriever，性别为F，月龄为12，体重为9.0

最佳答案

那是因为您要打印dog1的名称而不是dog2：

System.out.println("Dog2's name is " + dog1.getName()...
                                       ^^^