java - 从文件路径初始化对象变量

servername
|-- reports
|    |-- ABC
|    |    |-- COB02May2017
|    |    |    |-- pnlreport.pdf
|    |    |    |-- balancereport.pdf
|    |    |-- COB03May2017
|    |-- CustomerB
|    |    |-- COB02May2017
|    |    |-- COB03May2017
|    |    |    |-- balancereport.pdf
|    |-- 01CFG
|    |    |-- COB03Sep2017

我有上面的目录树保存我的客户报告。

我有以下ReportDeliverable模型：

public class ReportDeliverable {

    private String reportId;
    private String reportName;
    private String customer;
    private String format;
    private Date cobDate;
}

ReportSchedule：

public class ReportSchedule {

    private final String schedule;
    private final String reportId;
    private final String filePattern;
    private final String format;
    private final String filePath;

}

我有以下类，负责提供报告可交付对象的列表：

@Service
public class FileServiceImpl implements FileService {


    @Value("${reports.source-path}")
    private String sourcePath;


    @Override
    public List<ReportDeliverable> getReportDeliverables(ReportSchedule reportSchedule) {
        List<ReportDeliverable> reportDeliverables = new ArrayList<>();
        List<Path> filesToProcess = getFilesToProcess(reportSchedule);

        filesToProcess.forEach(path -> {
            //for each path returned, extract and initialise ReportDeliverable object
            ReportDeliverable reportDeliverable = new ReportDeliverable();
            //reportDeliverable.setReportName(); > pnlreport.xls
            //reportDeliverable.setFormat(); >  > PDF
            //reportDeliverable.setCobDate(); > 26-SEP-2017
            //reportDeliverable.setClient(); > CustomerA
            //reportDeliverable.setFilePath(); > \servername\reports\CustomerA\COB26Sep2017\pnlreport.pdf

            reportDeliverables.add(reportDeliverable);
        });

        return reportDeliverables;
    }

    public List<Path> getFilesToProcess(ReportSchedule reportSchedule) {

        String pattern = reportSchedule.getFilePattern(); //e.g. pnlreport
        String format = reportSchedule.getFormat(); // PDF

        //return full paths from here based on report criteria for COB that is T-1 (day before today). ignore the rest
        // e.g. if today is 27/09/2017
        //return -> \servername\reports\CustomerA\COB26Sep2017\pnlreport.pdf, \servername\reports\CustomerB\COB26Sep2017\pnlreport.PDF

        return path;
    }
}

每天创建一个目录，其名称为上述目录结构的COB- {prior-day-date}。使用Java 8


我需要一些帮助，以返回所有与paths中保存的条件有关的文件ReportSchedules。我试图在getFilesToProcess(ReportSchedule reportSchedule)中的注释中进行解释
从路径中，我需要初始化ReportDeliverable字段，在注释getReportDeliverables(ReportSchedule reportSchedule)中再次说明

最佳答案

我对您的问题的理解是如何在目录结构中回溯地查找适合目录中特定模式的文件，这些文件的命名方式包括遵循特定格式规则的格式化日期。这是我想出的。有可能进行优化，但这应该是一个起点。

如果我对您的问题的理解不正确，则可以改写一下，以便我纠正答案。

import java.io.File;
import java.nio.file.Path;
import java.nio.file.Paths;
import java.text.SimpleDateFormat;
import java.util.ArrayList;
import java.util.Calendar;
import java.util.List;
import java.util.Locale;

public class RetrievePathsOfYesterday {

    public final static void main(String[] args) {
        String pattern = "pnlreport";
        String format = "PDF";
        String baseDir = "F:/Test";
        switch(args.length) {
        case 3:
            format = args[2];
        case 2:
            pattern = args[1];
        case 1:
            baseDir = args[0];
        }
        File root = new File(baseDir);
        File[] customerDirs = root.listFiles(file -> file.getName().toLowerCase(Locale.ENGLISH).startsWith("customer"));
        ArrayList<Path> result = new ArrayList<>();
        for (int i = 0; i < customerDirs.length; i++) {
            result.addAll(getFilesToProcess(customerDirs[i], pattern, format));
        }
        System.out.println(result);
    }

    public static List<Path> getFilesToProcess(File baseDir, String pattern, String format) {
        pattern = pattern.toLowerCase(Locale.ENGLISH);
        format = "." + format.toLowerCase(Locale.ENGLISH);
        Calendar now = Calendar.getInstance();
        now.add(Calendar.DAY_OF_YEAR, -1);
        SimpleDateFormat sdf = new SimpleDateFormat("ddMMMyyyy", Locale.ENGLISH);
        File startDir = new File(baseDir, "COB" + sdf.format(now.getTime()));
        ArrayList<Path> result = new ArrayList<>();
        getFilesToProcess(result, startDir, pattern, format);
        return result;
    }

    private static void getFilesToProcess(List<Path> resList, File baseDir, String pattern, String format) {
        System.out.println("processing " + baseDir.getAbsolutePath());
        if (!baseDir.exists()) {
            return;
        }
        File[] files = baseDir.listFiles(pathName -> {
            System.out.println("filter " + pathName.getName());
            if (pathName.isDirectory()) {
                return true;
            }
            if (!pathName.isFile()) {
                return false;
            }
            String name = pathName.getName().toLowerCase(Locale.ENGLISH);
            if (!name.startsWith(pattern)) {
                return false;
            }
            if (!name.endsWith(format)) {
                return false;
            }
            return true;
        });

        for (int i = 0; i < files.length; i++) {
            File current = files[i];
            System.out.println("Checking " + current.getAbsolutePath());
            if (current.isDirectory()) {
                getFilesToProcess(resList, current, pattern, format);
                continue;
            }
            resList.add(Paths.get(current.toURI()));
        }
    }
}

我使用以下目录结构测试了此代码：

kimmerin@harry /cygdrive/f
$ ls -R Test
Test:
CustomerA  CustomerB

Test/CustomerA:
COB26Sep2017

Test/CustomerA/COB26Sep2017:
pnlreport.pdf

Test/CustomerB:
COB26Sep2017

Test/CustomerB/COB26Sep2017:
otherreport.PDF

如果将Test替换为servername/report，则该结构应与问题中所述的结构完全相同。这是使用默认值启动类时的输出：


  过滤器pnlreport.pdf
  
  检查F：\ Test \ CustomerA \ COB26Sep2017 \ pnlreport.pdf
  
  处理F：\ Test \ CustomerB \ COB26Sep2017
  
  过滤其他报告.PDF
  
  [F：\ Test \ CustomerA \ COB26Sep2017 \ pnlreport.pdf]