javax.xml.parsers.DocumentBuilder
在 std:err
中打印一条消息。
下面的例子:
import java.io.*;
import javax.xml.parsers.*;
import org.w3c.dom.*;
public class FooMain {
public static Document slurpXML(String s) throws Exception {
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document rv = builder.parse(new ByteArrayInputStream(s.getBytes("UTF-8")));
return rv;
}
public static void main(String args[]) throws Exception {
try {
slurpXML("foo");
} catch (Exception e) {} // try to silence it - in vain
}
}
尽管有 try-catch 块,从命令行运行程序会产生:
$ java -classpath dist/foo.jar FooMain
[Fatal Error] :1:1: Content is not allowed in prolog.
我想在控制台实用程序中使用
DocumentBuilder
并且我不希望输出困惑。有没有办法让它静音? 最佳答案
创建一个什么都不做的自定义 ErrorHandler
import java.io.*;
import javax.xml.parsers.*;
import org.w3c.dom.*;
import org.xml.sax.ErrorHandler;
import org.xml.sax.SAXException;
import org.xml.sax.SAXParseException;
public class FooMain {
public static Document slurpXML(String s) throws Exception {
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
builder.setErrorHandler(new ErrorHandler() {
@Override
public void warning(SAXParseException exception) throws SAXException {
}
@Override
public void error(SAXParseException exception) throws SAXException {
}
@Override
public void fatalError(SAXParseException exception) throws SAXException {
}
});
Document rv = builder.parse(new ByteArrayInputStream(s.getBytes("UTF-8")));
return rv;
}
public static void main(String args[]) throws Exception {
try {
slurpXML("foo");
} catch (Throwable e) {} // try to silence it - in vain
}
}
关于javax.xml.parsers.DocumentBuilder 解析悄悄不可能?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/21001961/