有没有一种方法可以找到不一定是二进制的树的高度?对于二叉树的高度,有很多算法,但是对于非二叉树,它们都不起作用。

最佳答案

就在这里。递归方法可能类似于:

public class TreeNode<T>{
    private List<TreeNode<T>> children = new ArrayList<TreeNode<T>>();
    private T data = null;

    public TreeNode(T data){
        this.data = data;
    }

    public List<TreeNode<T>> getChildren(){
        return children;
    }

    public void setChild(TreeNode<T> children){
        this.children.add(children);
    }

    public Integer getHeight(TreeNode<T> root){
        if(root == null) return 0;
        Integer h=0;

        for(TreeNode<T> n : root.getChildren()){
            h = Math.max(h, getHeight(n));
        }
        return h+1;
    }
}

测试:
public static void main(String[] args){
    TreeNode<Integer> root = new TreeNode<Integer>(50);
    TreeNode<Integer> c1 = new TreeNode<Integer>(100);
    TreeNode<Integer> c2= new TreeNode<Integer>(10);
    TreeNode<Integer> c3 = new TreeNode<Integer>(-5);
    TreeNode<Integer> c4 = new TreeNode<Integer>(0);
    TreeNode<Integer> c5 = new TreeNode<Integer>(33);
    TreeNode<Integer> c6 = new TreeNode<Integer>(1);
    TreeNode<Integer> c7 = new TreeNode<Integer>(2);
    TreeNode<Integer> c8 = new TreeNode<Integer>(3);
    TreeNode<Integer> c9 = new TreeNode<Integer>(300);
    TreeNode<Integer> c10 = new TreeNode<Integer>(350);

    root.setChild(c1);
    root.setChild(c2);
    c2.setChild(c3);
    c3.setChild(c4);
    c3.setChild(c5);
    c3.setChild(c6);
    c3.setChild(c7);
    c3.setChild(c8);

    c1.setChild(c9);
    c1.setChild(c10);

    System.out.print("Pre order: \n");
    root.dfs(root, 0);
    System.out.print("\nPost order: \n");
    root.dfs(root, 1);
    System.out.print("\nBFS: \n");
    root.bfs(root);
    System.out.println();
    System.out.print("\nHeigth: \n");
    System.out.println(root.getHeight(root));
}

结果:
Heigth:
4

编辑:返回4,而不是3如前所述

07-28 12:01