我有时间跨度：
long dateStart = System.currentTimeMillis();
long dateEnd = System.currentTimeMillis() + 60*60*1000;
我想检查
mHour和mMinute是否位于dateStart和dateEnd.之间例如
mHour = 11和mMinute = 22，所以我想要的是dateStart < 11:22 < dateEnd在这里日期不重要。
另一个例子：
2014/10/25 15:46 < 10:30 < 2014/10/26 : 15:45, the expected result will be true.
Because, 2014/10/26 10:30 < 2014/10/26 : 15:45
澄清：
the lower and upper bounds of dateStart and dateEnd cannot exceed 1 day span. So, if dateStart is
2014/10/26 23:59, the most dateEnd would be 2014/10/27 23:58.
我已经做到了，但是没有成功：
compareTime(dateStart ,dateEnd ,mHour ,mMinute );
public static void compareTime(long time1, long time2, int mHour, int mMinute) throws ParseException {
Calendar calendar1 = Calendar.getInstance();
calendar1.setTime(new Date(time2));
Calendar calendar2 = Calendar.getInstance();
calendar2.setTime(new Date(time1));
calendar2.add(Calendar.DATE, 1);
String someRandomTime = selectedHour + ":" + selectedminute;
Date d = new SimpleDateFormat("HH:mm").parse(someRandomTime);
Calendar calendar3 = Calendar.getInstance();
calendar3.setTime(d);
calendar3.add(Calendar.DATE, 1);
Date x = calendar3.getTime();
if (x.after(calendar1.getTime()) && x.before(calendar2.getTime()))
System.out.println(true);
}
最佳答案
只是与Joda-time库有关。 compareTime方法将如下所示：
/**
* @param time1 dateFrom in millis. E.g. returned by System.currentTimeMillis()
* @param time2 dateTo in millis
* @param mHour hours in your time zone
* @param mMinute minutes in your time zone
*/
public static boolean compareTime(long time1, long time2, int mHour, int mMinute)
{
final LocalTime timeFrom = new LocalTime(time1);
final LocalTime timeTo = new LocalTime(time2);
final LocalTime time = new LocalTime(mHour, mMinute);
final boolean isSameDay = timeFrom.isBefore(timeTo); // it is correct, because (time2 - time1 < 24 hours)
return isSameDay ? (time.isAfter(timeFrom) && time.isBefore(timeTo))
: (time.isAfter(timeFrom) || time.isBefore(timeTo));
}