我有一个TileGrid类,它包含一个std::vector< std::vector<Tile> >。访问 vector 中的Tile对象有效,但是我不能更改其属性吗?为了完整起见,这里是所有相关的类:

tilegrid.h

#include <vector>
#include "tile.h"

class TileGrid {

public:
  TileGrid();
  TileGrid(unsigned int rows, unsigned int cols);
  virtual ~TileGrid();
  unsigned int getRows() const { return rows_; };
  unsigned int getCols() const { return cols_; };
  Tile atIndex(unsigned int row, unsigned int col) const { return tiles_[row].at(col); };

private:
  std::vector< std::vector<Tile> > tiles_;
  unsigned int rows_;
  unsigned int cols_;

};

tilegrid.cpp
#include "tilegrid.h"

TileGrid::TileGrid() : rows_(0), cols_(0) {
}

TileGrid::TileGrid(unsigned int rows, unsigned int cols) : rows_(rows), cols_(cols) {
  tiles_.clear();
  for (unsigned int y = 0; y < rows_; y++) {
    std::vector<Tile> horizontalTiles;
    for (unsigned int x = 0; x < cols_; x++) {
      horizontalTiles.push_back(Tile());
    }
    tiles_.push_back(horizontalTiles);
  }
}

TileGrid::~TileGrid() {
}

平铺
class Tile {

public:
  Tile();
  virtual ~Tile();
  bool isActive() const { return isActive_; };
  void setActive(bool status) { isActive_ = status; };

private:
  bool isActive_;

};

tile.cpp
#include "tile.h"

Tile::Tile() : isActive_(false) {
}

Tile::~Tile() {
}

main.cpp
#include "tilegrid.h"
#include <iostream>

int main() {

  TileGrid tg(20, 20);

  for (unsigned int i = 0; i < tg.getRows(); i++) {
    for (unsigned int j = 0; j < tg.getCols(); j++) {
      if (tg.atIndex(i, j).isActive()) {
        std::cout << i << "," << j << " is active" << std::endl;
      } else {
        std::cout << i << "," << j << " is NOT active" << std::endl;
      }
    }
  }

  // This is all working. But when I for example use the setActive function, nothing changes:

  tg.atIndex(1, 0).setActive(true);

  // When I print it again, the values are still the ones that were set in the constructor

  for (unsigned int i = 0; i < tg.getRows(); i++) {
    for (unsigned int j = 0; j < tg.getCols(); j++) {
      if (tg.atIndex(i, j).isActive()) {
        std::cout << i << "," << j << " is active" << std::endl;
      } else {
        std::cout << i << "," << j << " is NOT active" << std::endl;
      }
    }
  }

  return 0;

}

对于所有这些代码,我真的感到很抱歉...我试图将其尽量缩短,但我认为最好将其全部发布!

是的,我的问题是setActive函数。当我只创建一个Tile并调用其setActive函数时,一切正常,但是当我通过TileGrid对象调用它时,它将无法正常工作。

我已经尝试了几个小时才能自行解决此问题,但我再也想不起来了。我真的很绝望,可以请您帮我一下吗?

最佳答案

在您的方法中:

Tile atIndex(unsigned int row, unsigned int col) const

您应该返回对Tile的引用:
Tile& atIndex(unsigned int row, unsigned int col)

现在您正在返回副本,这就是为什么修改不起作用的原因。另外它也不应该是const,否则您将得到编译器错误。

08-06 00:40