我开发了一个UITableView
,其中有些单元格可能具有子单元格。
例:
我的应用程序允许用户移动单元格的位置,但是,当一个表中有一个或多个带有子单元格的单元格时,我将它们全部折叠起来,以仅允许移动具有相同标识(或相同级别)的单元格
如果表很长,当我折叠带有子元素的单元格时,我将使用该单元格的indexPath从表中删除子元素。我的问题是某些单元格不在内存中,所以我崩溃了。
我如何才能检测到未显示某个单元格,以便仅从dataSource中删除该元素?
这是我折叠/展开元素的方法:
- (void)expandCollapseSubtasks:(UIButton *)sender
{
CGPoint buttonPosition = [sender convertPoint:CGPointZero toView:_taskTableView]; //when CGPoint = 0,0 not remove cells?
NSIndexPath *indexPath = [_taskTableView indexPathForRowAtPoint:buttonPosition];
if (indexPath != nil)
{
Task *task = [_tasks objectAtIndex:indexPath.row];
TaskTitleCell *cell = (TaskTitleCell *)[_taskTableView cellForRowAtIndexPath:indexPath];
UILabel *subtasksNumberLabel = (UILabel *)[cell viewWithTag:107];
UIButton *subtasksButton = (UIButton *)[cell viewWithTag:108];
NSMutableArray *subtasksIndexPaths = [[NSMutableArray alloc] init];
NSNumber *hidden;
//Expand
if (!subtasksButton.selected){
hidden = @0;
subtasksNumberLabel.textColor = [UIColor colorWithRed:72.0/255.0 green:175.0/255.0 blue:237.0/255.0 alpha:1.0];
NSDictionary *subtasksAndIndexesDictionary = [task getSubtasksIndexesInTaskCollection:_tasks ofList:task.list];
NSIndexSet *indexes = [subtasksAndIndexesDictionary objectForKey:@"indexes"];
NSArray *subtasks = [subtasksAndIndexesDictionary objectForKey:@"subtasks"];
[_tasks insertObjects:subtasks atIndexes:indexes];
[indexes enumerateIndexesUsingBlock:^(NSUInteger idx, BOOL *stop) {
NSIndexPath *subtaskIndexPath = [NSIndexPath indexPathForRow:idx inSection:0];
[subtasksIndexPaths addObject:subtaskIndexPath];
}];
[_taskTableView insertRowsAtIndexPaths:subtasksIndexPaths withRowAnimation:UITableViewRowAnimationTop];
//Collapse
}else{
hidden = @1;
subtasksNumberLabel.textColor = [UIColor whiteColor];
NSArray *subtasks = [task getSubtasks];
[_tasks removeObjectsInArray:subtasks];
for (int i=1;i<=subtasks.count; i++){
NSIndexPath *subtaskIndexPath = [NSIndexPath indexPathForRow:indexPath.row+i inSection:0];
[subtasksIndexPaths addObject:subtaskIndexPath];
}
[_taskTableView deleteRowsAtIndexPaths:subtasksIndexPaths withRowAnimation:UITableViewRowAnimationBottom];
}
subtasksButton.selected = !subtasksButton.selected;
task.hidesubtasks = hidden;
[[NSManagedObjectContext defaultContext] saveToPersistentStoreAndWait];
}
}
和电话
NSIndexPath *indexPath = [NSIndexPath indexPathForRow:idx inSection:0];
UITableViewCell *cell = [_taskTableView cellForRowAtIndexPath:indexPath];
UIButton *subtasksButton = (UIButton *)[cell viewWithTag:108];
[self expandCollapseSubtasks:subtasksButton];
其中
idx
是元素在数据源中的位置 最佳答案
您可以获取所有可见单元格的NSIndexPath数组:
NSArray *array = [self.tableView indexPathsForVisibleRows];
您还可以获取单元格本身而不是NSIndexPath的数组:
[tableView visibleCells]
那就是您需要找出不可见的单元格。
关于ios - 如何知道UITableView是否未显示UITableViewCell,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/32460511/