我已经看到了Restify的示例,其中所有端点都位于根目录上:/ users,/ data等。我知道可以像这样实现嵌套:

server.get('/users/:user/data/:id', returnData);


req.params变量将具有所有请求参数。例:

{ user: '45', id: '80' }


如果我的应用程序没有几个端点,这似乎可以很好地工作,但是如果我有一个要通过REST API公开的深度和分支数据结构,该怎么办?就像是:

{
  stuff: {
    points: {
      colors: {
        shinyThings: {},
        dullThings: {}
      }
    },
    ships: {
      enterprises: {},
      starDestroyers: {}
    }
  },
  things: {},
}


不得不手动编写通往所有这些端点的路径似乎并不正确。我最终得到许多路径定义和类似的内容:

server.put('/stuff/:stuff/points/:points/colors/:colors/shinyThings/:shinyThings', returnShinyThing);


使用Restify有更简单的方法吗?

最佳答案

尽管我确信还有更好的选择,但我已经想出了一种方法:

1)创建模块以处理端点上的某些操作。这些模块将成为中央路由器模块所必需的。示例stuff.js

exports.list = function(req, res, next) {
  // Code to handle a GET request to /stuff
};

exports.create = function(req, res, next) {
  // Code to handle a POST request to /stuff
};

exports.show = function(req, res, next) {
  // Code to handle a GET request to /stuff/:id
};

exports.update = function(req, res, next) {
  // Code to handle a PUT request to /stuff/:id
};

exports.destroy = function(req, res, next) {
  // Code to handle a DELETE request to /stuff/:id
};


2)在路由器模块中,定义动作的映射-> http动词:

var actions = {
  list: 'get',
  create: 'post',
  show: 'get',
  update: 'put',
  destroy: 'del'
}


3)创建一个表示数据结构的对象,如下所示:

var schema = {
  stuff: {
    _actions: require('./stuff'),
    points: {
      _actions: require('./points'),
      colors: {
        _actions: require('./colors'),
        shinyThings: {_actions: require('./shinyThings')},
        dullThings: {_actions: require('./dullThings')}
      }
    },
    ships: {
      _actions: require('./ships'),
      enterprises: {_actions: require('./enterprises')},
      starDestroyers: {_actions: require('./starDestroyers')}
    }
  },
  things: {_actions: require('./things')},
}


4)在路由器初始化期间,应用程序将其传递给Restify服务器对象以将路由附加到该对象。在初始化期间,递归函数遍历架构对象,当找到_actions键时,它将调用第二个函数,该函数将给定路径上的路由处理程序附加到给定服务器对象:

(function addPathHandlers(object, path) {
  for (var key in object) {
    if (key === '_actions') addActions(object, path);
    else if (typeof object[key] === 'object') {
      var single = en.singularize(path.split('/').pop());

      if (path.charAt(path.length - 1) !== '/') {
        path += ['/:', single, '_id/'].join('');
      }

      addPathHandlers(object[key], path + key);
    }
  }
})(schema, '/');

function addActions(object, path) {
  // Actions that require a specific resource id
  var individualActions = ['show', 'update', 'destroy'];

  for (var action in object._actions) {
    var verb = actions[action];

    if (verb) {
      var reqPath = path;
      if (individualActions.indexOf(action) !== -1) reqPath += '/:id';

      server[verb](reqPath, object._actions[action]);
    }
  }
}


注意:这利用了lingo模块(即en.singularize()函数)。由于我删除了功能的非关键部分,因此它也得到了一些简化,但是它应该是完整的功能。

尽管它不是那么精致和易于使用,但它的灵感来自于看了快速资源的实现方式。

关于javascript - 如何使用restify.js处理深层和复杂的数据结构,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/13726718/

10-12 13:07