我正在使用内置相机解码条形码,我使用 capElement.Source.CapturePhotoToStreamAsync
执行此操作以从预览中捕获照片。它可以工作,但会在短时间内卡住应用程序,这感觉非常笨拙且有问题。
所以我想在后台这样做,同时至少在处理照片时留下一个响应式用户界面。
到目前为止,我想出了这个来捕获视频流:
private async void ScanInBackground()
{
bool failedScan = true;
var stream = new InMemoryRandomAccessStream();
await capElement.Source.StartRecordToStreamAsync(MediaEncodingProfile.CreateWmv(VideoEncodingQuality.HD1080p), stream);
while(failedScan)
{
Byte[] bytes = await GetBytesFromStream(stream);
//How to split the bytes into frames?
Task.Delay(50);
}
Dispatcher.RunAsync(CoreDispatcherPriority.Low,() => StopCap());
}
以及从流中获取字节的此方法:
public static async Task<byte[]> GetBytesFromStream(IRandomAccessStream randomStream)
{
var reader = new DataReader(randomStream.GetInputStreamAt(0));
var bytes = new byte[randomStream.Size];
try
{
await reader.LoadAsync((uint)randomStream.Size); reader.ReadBytes(bytes);
}
catch(Exception ex)
{
Logger.LogExceptionAsync(ex, "GetBytesFromStream");
}
return bytes;
}
从
ScanInBackground
的评论中,您可以看到我不知道如何将流拆分为照片/帧。 最佳答案
Microsoft github 页面上有一个相关示例,尽管它们针对的是 Windows 10。您可能有兴趣迁移您的项目以获得此功能。
GetPreviewFrame :此示例将捕获预览帧而不是完整的照片。一旦有了预览帧,它就可以读取和编辑其上的像素。
这是相关部分:
private async Task GetPreviewFrameAsSoftwareBitmapAsync()
{
// Get information about the preview
var previewProperties = _mediaCapture.VideoDeviceController.GetMediaStreamProperties(MediaStreamType.VideoPreview) as VideoEncodingProperties;
// Create the video frame to request a SoftwareBitmap preview frame
var videoFrame = new VideoFrame(BitmapPixelFormat.Bgra8, (int)previewProperties.Width, (int)previewProperties.Height);
// Capture the preview frame
using (var currentFrame = await _mediaCapture.GetPreviewFrameAsync(videoFrame))
{
// Collect the resulting frame
SoftwareBitmap previewFrame = currentFrame.SoftwareBitmap;
// Add a simple green filter effect to the SoftwareBitmap
EditPixels(previewFrame);
}
}
private unsafe void EditPixels(SoftwareBitmap bitmap)
{
// Effect is hard-coded to operate on BGRA8 format only
if (bitmap.BitmapPixelFormat == BitmapPixelFormat.Bgra8)
{
// In BGRA8 format, each pixel is defined by 4 bytes
const int BYTES_PER_PIXEL = 4;
using (var buffer = bitmap.LockBuffer(BitmapBufferAccessMode.ReadWrite))
using (var reference = buffer.CreateReference())
{
// Get a pointer to the pixel buffer
byte* data;
uint capacity;
((IMemoryBufferByteAccess)reference).GetBuffer(out data, out capacity);
// Get information about the BitmapBuffer
var desc = buffer.GetPlaneDescription(0);
// Iterate over all pixels
for (uint row = 0; row < desc.Height; row++)
{
for (uint col = 0; col < desc.Width; col++)
{
// Index of the current pixel in the buffer (defined by the next 4 bytes, BGRA8)
var currPixel = desc.StartIndex + desc.Stride * row + BYTES_PER_PIXEL * col;
// Read the current pixel information into b,g,r channels (leave out alpha channel)
var b = data[currPixel + 0]; // Blue
var g = data[currPixel + 1]; // Green
var r = data[currPixel + 2]; // Red
// Boost the green channel, leave the other two untouched
data[currPixel + 0] = b;
data[currPixel + 1] = (byte)Math.Min(g + 80, 255);
data[currPixel + 2] = r;
}
}
}
}
}
并在您的类(class)之外声明:
[ComImport]
[Guid("5b0d3235-4dba-4d44-865e-8f1d0e4fd04d")]
[InterfaceType(ComInterfaceType.InterfaceIsIUnknown)]
unsafe interface IMemoryBufferByteAccess
{
void GetBuffer(out byte* buffer, out uint capacity);
}
当然,您的项目必须允许不安全的代码才能使所有这些工作正常进行。
仔细查看示例以了解如何获取所有详细信息。或者,要进行演练,您可以观看最近的//build/ session 中的 camera session,其中包括一些相机示例的演练。
关于c# - WinRT 从视频流中提取帧,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/31578754/