java - 即使数字太大，它仍在处理中(忽略，我已修复它)

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想改善这个问题吗？ Update the question，所以它是on-topic，用于堆栈溢出。

5年前关闭。

import java.io.*;

导入java.util。*;

公共课程CH04 {

// Constants Declaration Section
//******************************

public static void main(String[] args) throws FileNotFoundException {
    // TODO Auto-generated method stub

    // Variables Declaration Section
    //******************************
    int  quarters;
    int  dimes;
    int  nickles;
    int  numberOfQuarters;
    int  numberOfDimes;
    int remainingAmount;
    int numberOfNickles;
    int numberOfPennies;
    int maxSize;

    // Variables Initialization Section
    //*********************************
    Scanner data = new Scanner(new File("C:\\testing3.txt"));     //Reads from text file
    ArrayList<Double> datadata = new ArrayList<Double>();    //Creates Array
    quarters = 25;
    dimes = 10;
    nickles = 5;
    maxSize = 10000;



    // Code Section
    //*************
    while(data.hasNextDouble())    //Retrieves data from text file and places it in array
    {
        datadata.add(data.nextDouble());  //Retrieves data from text file and places it in array
    }

    for (int i = 0; i < datadata.size(); i++)  //Loops through the data
    {
        double value = datadata.get(i);   //returns number found in file as a double 'value' then runs it through the calculator
        System.out.println(value);

        while(value > maxSize) //If value is greater than 10,000, it will be skipped and not read through the calculator
        {

        }

        remainingAmount = (int)Math.ceil((value) * 100);      //multiplies value by 100

        numberOfQuarters = remainingAmount / quarters;   //divides value by 25
        remainingAmount = remainingAmount % quarters;    //returns the remaining value

        numberOfDimes = remainingAmount / dimes;    //divides the remaining value by 10
        remainingAmount = remainingAmount % dimes;  //returns the remaining value of that

        numberOfNickles = remainingAmount / nickles;  //divides the remaining value from dimes by 5
        remainingAmount = remainingAmount % nickles;  //returns remaining value

        numberOfPennies = remainingAmount;   //divides remaining value by 1


        System.out.print("Your amount of $" + value + " consists of: \n" + numberOfQuarters +            //prints out the amount of quarters, dimes, nickels, pennies
                " quarteres, " + numberOfDimes + " dimes, " + numberOfNickles + " nickles, and " +       //that make up each value found inside the file.
                  numberOfPennies + " pennies");

        System.out.print("\n\n");

    }



    //Output Section
    //**************




    //Resource Cleaning
    //*****************
    data.close();

}

}

**Output:

10001.0
值太大，无法处理10001.0
您的$ 10001.0金额包括：
40004个季度，0个角钱，0个镍币和0个便士

9755.35
您的$ 9755.35金额包括：
39021个季度，1个角钱，0个镍币和0个便士

875.4
您的$ 875.4金额包括：
3501个硬币，1个角钱，1个镍币和0个便士

78.99
您的$ 78.99金额包括：
315个季度，2个角钱，0个镍币和4个便士

5.0
您的$ 5.0金额包括：
20个季度，0个角钱，0个镍币和0个便士

0.7
您的$ 0.7金额包括：
2个季度，2个角钱，0个镍币和0个便士

使用的值：[10001.0、9755.35、875.4、78.99、5.0、0.7]
**

由于某种原因，我将输出的斜体部分减少了1便士。这让我感到困惑，因为其余的输出是正确的。

我的文本值内的值是：

10,001.00 -
9,755.35 -
875.40 -
78.99 -
5.00 -
0.70

最佳答案

我不会写代码本身。我想以手工为例。调试此类问题的一般经验法则是：从头到尾或从​​头开始。
除法工作正常，因此必须在一开始就发生，这就是将您的值转换为整数的地方。如果您检查值* 100的乘积结果，那么您会看到7898.999999999999，而不是您期望的7899。您应该使用Math.ceil来获得正确的值，如下所示：

 int result = (int)Math.ceil(value * 100);

关于java - 即使数字太大，它仍在处理中(忽略，我已修复它)，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/28493800/