1003

 1 #include<iostream>
 2 #include<string>
 3 #include<vector>
 4 #include<algorithm>
 5 #include<iterator>
 6 #include<windows.h>
 7
 8 using namespace std;
 9
10 int main()
11 {
12     int n;
13     int cnt = 0;
14     string s;
15      cin >> n;
16     while (cnt != n)
17     {
18         int a = 0, b = 0, c = 0;
19         ++cnt;
20         cin >> s;
21         auto iter1 = find(s.begin(), s.end(), 'P');
22         auto iter2 = find(s.begin(), s.end(), 'T');
23         if (iter1 == s.end() || iter2 == s.end())
24         {
25             cout << "NO" << endl;
26             continue;
27         }
28         auto iter = s.begin();
29         for (; iter != iter1; ++iter)
30         {
31             if (*iter != 'A')
32                 break;
33             ++a;
34         }
35         if(iter != iter1)
36         {
37             cout << "NO" << endl;
38             continue;
39         }
40         for (++iter; iter != iter2; ++iter)
41         {
42             if (*iter != 'A')
43                 break;
44             ++b;
45         }
46         if (iter != iter2)
47         {
48             cout << "NO" << endl;
49             continue;
50         }
51         for (++iter; iter != s.end(); ++iter)
52         {
53             if (*iter != 'A')
54                 break;
55             ++c;
56         }
57         if (iter != s.end())
58         {
59             cout << "NO" << endl;
60             continue;
61         }
62         if (b == 0 || a*b != c)
63         {
64             cout << "NO" << endl;
65             continue;
66         }
67         cout << "YES" << endl;
68     }
69
70     system("pause");
71     return 0;
72 }

本题是一道数学问题（找规律），需满足'P'之前'A'的个数乘以'P'与'T'之间'A'的个数='T'之后'A'的个数。注意'P'与'T'之间必须要有'A'。