因此,我尝试读取每个块包含4个字节的二进制文件,并且在对文件进行十六进制转储时,输出为:0000000 0022 0000 6261 6463 3030 3030 6261 64630000010 3030 3030 6261 6463 3030 3030 6261 6463*00000d0 3030 3030 6261 6463 3030 3030 000a00000dd
(抱歉,每行数字之间不应有一行)
但是,当将这些值读入数组时,这就是我得到的输出:34 61000000 30646362 61303030 30646362 61303030 30646362 61303030 30646362 2283030 0 44c5bbc0 7fff 22 0 14fea515 7f68 0 0 22 0 22 0 4007b2 0 1 0 1000 0 2289010 0 44c5bbc0 7f
我已经在网上遵循了很多说明,但我真的不确定从这里出发。
这是我正在使用的代码:
#include <stdlib.h>
#include <string.h>
#include <stdio.h>
int main(int argc, char** argv)
{
unsigned char buffer[1];
FILE *filePointer;
filePointer = fopen(argv[1], "rb");
//unsigned char buffer[filePointer];
int readVal = 0;
readVal = fread(buffer, sizeof(buffer), 1, filePointer);
if (readVal == 0)
{
printf("File did not read anything\n");
}
int size = buffer[0];
/*int i = 1;
for(; i < 1; i++)
{
printf("%x ", buffer[i]);
}
*/
//int size = buffer[0];
printf("%d\n", size);
unsigned int array[size];
int otherDataElements;
otherDataElements = fread(array, sizeof(buffer), size, filePointer);
if (otherDataElements == 0)
{
printf("There was nothing there!");
}
int j = 0;
for (; j < size; j++)
{
printf("%x ", array[j]);
}
return 0;
}
有一些代码被注释掉了,请忽略它。谢谢!
最佳答案
什么是size
?字节数?或整数?
这似乎令人怀疑:
otherDataElements = fread(array, sizeof(buffer), size, filePointer);
尝试更改为此:
otherDataElements = fread(array, sizeof(unsigned int), size/sizeof(unsigned int), filePointer);
因为array是无符号整数的
array
,并且fread
的第二个参数要求您读取每个元素的大小。如果您想将文件内容解释为4字节整数数组,则文件长度也应该是4的倍数。无论如何,此程序在我的机器上的输出是(这与您刚刚向程序中添加写入数据以进行测试的程序类似,并且我简化了阅读):
#include <stdlib.h>
#include <string.h>
#include <stdio.h>
void test()
{
unsigned char buffer[1];
FILE *filePointer;
filePointer = fopen("/Users/macbookair/Documents/test/test/t.bin", "rb");
//unsigned char buffer[filePointer];
//readVal = fread(buffer, sizeof(buffer), 1, filePointer);
//if (readVal == 0)
//{
// printf("File did not read anything\n");
// }
//int size = 4;
/*int i = 1;
for(; i < 1; i++)
{
printf("%x ", buffer[i]);
}
*/
//int size = buffer[0];
//printf("%d\n", size);
unsigned int array[4] = {0};
int otherDataElements;
int nrOfInts = 1; // In this test method we only want to read 1 integer from file, we assume there is one integer only
otherDataElements = fread(array, sizeof(unsigned int), nrOfInts, filePointer);
if (otherDataElements == 0)
{
printf("There was nothing there!");
}
int j = 0;
for (; j < nrOfInts; j++)
{
printf("%x ", array[j]);
}
}
int main(int argc, const char * argv[])
{
// Just do a test write to file. Write 4 bytes to read back later.
FILE *write_ptr;
unsigned char buffer[4] = {0,1,2,3};
write_ptr = fopen("/Users/macbookair/Documents/test/test/t.bin","wb");
fwrite(buffer,sizeof(buffer),1,write_ptr);
fclose(write_ptr);
// Call our method for reading the data
test();
return 0;
}
这个:
3020100
您可以看到输出被交换了,但这是由于字节顺序的-当我的计算机将字节00 01 02 03解释为整数的字节时,它是以小字节顺序的方式进行的-因此输出为整数03020100。您可能需要考虑一下同样在你的情况下。因此,就我而言,它运行良好。
关于c - 用C读取一个二进制文件,然后将文件中的数据与我已读入的文件进行匹配,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/28239081/