python - python的 war 卡片游戏

我正在尝试制作战争卡片游戏，但是我很难将代码连接起来。我不断收到未定义deck1的错误。我不明白为什么会这样。我试图将deck1和deck2连接到playerA = deck1.pop，依此类推。谢谢您的帮助！

import random
total = {
   'winA':0,
   'winB':0
}

def shuffleDeck():
    suits = {'\u2660', '\u2661', '\u2662', '\u2663'}
    ranks = {'2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K', 'A'}
    deck = []

for suit in suits:
    for rank in ranks:
        deck.append(rank+' '+suit)

random.shuffle(deck)
return deck

def dealDecks(deck):
    deck1 = deck[:26]
    deck2= deck[26:]
    hand = []
    return hand

def total(hand):
    values = {'2':2, '3':3, '4':4, '5':5, '6':6, '7':7, '8':8, '9':9, '1':10,
          'J':11, 'Q':12, 'K':13,'A':14}

def war(playerA, playerB):
    if playerA==playerB:
        print("Tie")
    elif playerA > playerB:
        print("Winner:Player A")
        return 1
    else:
        print("Winner:player B")
        return -1

def process_game(playerA,playerB):
    result = game(p1c,p2c)
    if result == -1:
        total['winB'] += 1
    else:
        total['winA'] += 1

deck = shuffleDeck()

dealDecks(deck);

gameplay = input("Ready to play a round: ")

while gameplay == 'y':

    playerA = deck1.pop(random.choice(deck1))
    playerB = deck2.pop(random.choice(deck2))
    print("Player A: {}. \nPlayer B: {}. \n".format(playerA,playerB))
    gameplay = input("Ready to play a round: ")

if total['winA'] > total['winB']:
    print("PlayerA won overall with a total of {} wins".format(total['winA']))
else:
    print("PlayerB won overall with a total of {} wins".format(total['winB']))

最佳答案

当前，dealDecks并没有真正按照它说的去做。为什么创建并return一个空列表：

def dealDecks(deck):
    deck1 = deck[:26]
    deck2= deck[26:]
    hand = []
    return hand

然后被忽略：

dealDecks(deck);

因此，在deck1之外的任何地方都无法访问dealDecks。相反，实际上要返回并分配甲板的两半：

def split_deck(deck):
    middle = len(deck) // 2
    deck1 = deck[:middle]
    deck2 = deck[middle:]
    return deck1, deck2

deck1, deck2 = split_deck(deck)

请注意，我已经排除了“幻数”，将函数重命名为描述它的作用，并根据Python style guide (PEP-0008)采用了lowercase_with_underscores。