我有三个过程，一个父亲和两个儿子，因为儿子们继承了我分叉之前创建的所有东西，因此我该如何访问我从儿子或父亲那里创建的字符串数组？
我想访问我创建的两个字符串数组，然后用儿子和父亲的名字命名为string_hashes和hash的分支？
谢谢您的帮助...
#include <unistd.h>
#include <sys/wait.h>
#include <sys/types.h>
#include <stdio.h>
#include <strings.h>
#include <sys/stat.h>
#include <fcntl.h>
#include <errno.h>
#define PIPE_NAME "np_workmaster"
#define max_chars_string 1000
#define n_childs 2
typedef struct
{
int a;
int b;
} numbers;
pid_t childs[n_childs];
void read_lines(char * filename, char (*pointer)[max_chars_string],int init_read,int n_lines);
void get_strings_hash(char (*pointer_strings)[max_chars_string],char (*pointer_hashes)[max_chars_string],int total_lines);
void worker(){ // meter as funcoes de ler passwords no filho
char * ant = "";
char hash_char;
printf("[%d] I'm the son!\n", getpid());
printf("[%d] My parent is: %d\n", getpid(), getppid());
exit(0);
}
void pparent(){// sera o ultimo processo a terminar mostrando as passwords ja recebidas do dispatcher que recebe dos outros filhos
printf("[%d] I'm the father!\n", getpid());
//dispatcher() // criar funcao dispatcher que envia dados ao outro processo...
int fd;
if ((fd=open(PIPE_NAME, O_WRONLY)) < 0)
{
perror("Cannot open pipe for writing: ");
exit(0);
}
// Do some work
while (1) {
// here i want to access arrays strings_hashes and hashes from the father and sons
printf("[CLIENT] Sending (%d,%d) for adding\n", n.a, n.b);
write(fd, &n, sizeof(numbers));
sleep(2);
}
return 0;
}
int main(int argc, char **argv)
{
char *filename;
int status;//status do processos filho
int resources[2];// numero de linhas que cada processo tem de ler
//char * chave_iniciadora = "";
int n_lines; //numero de linhas do ficheiro
int i = 0;
filename = (char*)malloc(strlen(argv[1])*sizeof(char)+1);
if(argc !=3){
fprintf(stderr, "Usage : %s [text_file] [cores]",argv[0]);
exit(0);
}
strcpy(filename,argv[1]);
n_lines = count_lines(filename); // contem o numero de linhas
//definicao arrays
char strings_hashes[n_lines][max_chars_string];//aray de string com as strings lidas do ficheiro
char hashes[n_lines][max_chars_string]; // array de strings com as hashes
char * pointer_string = &strings_hashes[0][0]; // ponteiro para o inicio do array das strings lidas do ficheiro
char * pointer_hashes = &hashes[0][0];//ponteiro para o inicio do array das hashes
//funcoes
share_resources(atoi(argv[2]),n_lines,resources);
read_lines(filename,strings_hashes,0,n_lines); // le as strings do ficheiro e passa para o array
get_strings_hash(strings_hashes,hashes,n_lines);
//
for(i = 0; i<n_lines;i++){
printf("%s",strings_hashes[i]);
}
for(i = 0; i<n_lines;i++){
printf("%s",hashes[i]);
}
//
for(i = 0; i <atoi(argv[2]);i++){
childs[i] = fork();
if(childs[i] == -1){
perror("Failed to fork");
return 1;
}
if (childs[i] == 0)
{
worker();
}
else
{
pparent();
wait(&status);
if (!status)
printf("\nOK\n");
else
printf("\nSomething is wrong...\n");
}
}
return 0;
}
///////////////////////////////////////////////////////////////////
//funcionar
void get_strings_hash(char (*pointer_strings)[max_chars_string],char (*pointer_hashes)[max_chars_string],int total_lines)//vai ao array de strings e corta a parte de hash e mete num array
{
int i = 0;
char *strings;
char *hash;
for(i = 0;i<total_lines;i++){
strings = (char*)malloc(strlen(pointer_strings)*sizeof(char)+1);
strcpy(strings,*pointer_strings);
hash = (char*)malloc(strlen(pointer_strings)*sizeof(char)+1);
find_hash(strings,hash);
strcpy(*pointer_hashes,hash);
pointer_hashes++;
pointer_strings++;
}
}
//funcionar
int count_lines(char * filename){
FILE *fp;
char str[max_chars_string];
int i =0;
if((fp = fopen("ficheiro_leitura.txt", "r"))==NULL) {
printf("Cannot open file.\n");
exit(1);
}
while(!feof(fp)) {
while(fgets(str, sizeof str, fp)) {
i++;
}
}
fclose(fp);
return i;
}
//funcionar
void read_lines(char * filename, char (*pointer)[max_chars_string],int init_read,int n_lines){
FILE *fp;
char str[max_chars_string];
int i =0;
if((fp = fopen(filename, "r"))==NULL) {
printf("Cannot open file.\n");
exit(1);
}
if(init_read>0 && init_read<=n_lines){
for(i = 0;i<init_read;i++){
fgets(str, sizeof str, fp);
for(i = init_read;i<n_lines;i++){
fgets(str, sizeof str, fp);
strcpy(*pointer, str); //copia para a posicao actula do ponteiro
pointer++;
}
}
}
if(init_read<=n_lines && init_read==0){
for(i = init_read;i<n_lines;i++){
fgets(str, sizeof str, fp);
strcpy(*pointer, str); //copia para a posicao actula do ponteiro
pointer++;
}
}
fclose(fp);
最佳答案
您不必做任何特别的事情。当前，您已经在main()中定义了它们。全局定义它们，或将它们传递给您的worker()（即子级）函数。
请记住，它们现在是同一事物的3个独立副本，因此，如果一个进程更改了它们，则这些更改将不会反映在其他进程中。如果这是您的意图，那么将它们放在共享内存中并用互斥锁保护它们可能是最简单的。
关于c - 从子进程访问在C linux中的 fork 之前创建的字符串数组，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/12849708/