我正在尝试生成一个2D魔术六边形晶格,(即我需要生成C语言中的点的坐标)看到附加的图像,该图看起来像一个洋葱结构,其中较大的一个内部有六边形,依此类推。
有人有主意吗?
注意:如果有人用其他语言回答,也可以,我只需要看一下就可以开始构建自己的代码。
提前致谢。
void generate_particles(void)
{/* Generates the particle - positions and charge
Here it indicated to use the hexagonal referential !!*/
int i,j;
int n=3; /*n represent the nth centered hex number given by the formula 3*n(n- )+1*/
double b;
b=(1.0/sqrt(sqrt(3)))*sqrt(2.0/par.NA);
/* b=1.0;*/
fprintf(stderr,"Distributing %d particles on the hexagonal lattice'...", par.N);
for (i=0;i<n-1;i++)
{
coo[i][0]= (sqrt(3)*i*b)/2.0;
for (j=0;j<(2*n-i-1);j++)
{
coo [i][1]= (-(2*n-i-2)*b)/2.0 + j*b;
fprintf(stderr," %lf %lf\n",coo[i][0],coo[i][1]);
/*plot the points with coordinate (x,y) here*/
if(coo[i][0]!=0)
{
fprintf(stderr," %lf %lf\n",-coo[i][0],coo[i][1]);
/*plot the points with coordinates (-x,y)*/
}
}
}fprintf(stderr," done\n\n");
}
void write_configuration_file(void)
{/* Writes the binary configuration file '<prefix>_config.<postfix>'
i.e velocities and coordinates. */
FILE *fp;
char filename[100];
char postfix_string[100];
int i;
fprintf(stderr,"Writing configuration file");
if (postfix >=0 ) {
if (postfix < 10) sprintf(postfix_string,"000%d",postfix);
else if (postfix < 100) sprintf(postfix_string, "00%d",postfix);
else if (postfix < 1000) sprintf(postfix_string, "0%d",postfix);
else if (postfix <10000) sprintf(postfix_string, "%d",postfix);
else sprintf(postfix_string, "_%d",postfix);
} else {
fprintf(stderr,"\nThe internal postfix is negative.\n\n");
exit(1);
}
sprintf(filename,"%s_config.%s",prefix,postfix_string);
fprintf(stderr," %s...", filename);
if ((fp = fopen(filename,"r")) != NULL) {
fprintf(stderr,"\nFile '%s' already exists. Don't want to overwrite it.\n\n",filename);
fclose(fp);
exit(1);
}
if ((fp = fopen(filename,"w")) == NULL) {
fprintf(stderr,"Could not create file '%s'.\n\n",filename);
exit(1);
}
/* postfix */
if (fwrite(&postfix,sizeof(int),1,fp) != 1)
{ fprintf(stderr,"fwrite error 1.\n\n"); exit(1); }
/* time */
if (fwrite(&ti,sizeof(int),1,fp) != 1)
{ fprintf(stderr,"fwrite error 2.\n\n"); exit(1); }
/* x,y coordinates of all particles/charges */
if (fwrite(coo,sizeof(double) ,2*par.N,fp) != 2*par.N)
{
fprintf(stderr,"fwrite error 4.\n\n"); exit(1); }
fclose(fp);
fprintf(stderr," done\n");
}
and the main program is:
int main()
{
int i;
printf("\n");
printf("\n");
printf("***************************************************************\n");
printf("* OK LETS GENERATE THE CONFIG FILE FOR MONTE CARLO SIMULATION *\n");
printf("***************************************************************\n\n");
read_wishlist();
init_ran1();
for (i=0; i<seed; i++) ran1_fast();
if (par.N > 0) generate_particles();
write_parameter_file();
write_configuration_file();
write_task_file();
/*final_test();*/
fprintf(stderr,"\n\nConfiguration successfully generated.\n\n");
}
好的,让我解释一下我的问题,事实上,您之前给我的代码是完美的,并且我能够在C和matlab中以六边形绘制粒子,但这只是在绘制;当我进行仿真时,问题是问题所在,每个粒子都有一个在我的代码中从0开始到参数N是可行的,但是我编写它的方式是只读取第13层上的13个粒子,所以请您帮我找到一种解决方案,以修改此方法,以便每个粒子都有一个提前协调谢谢。
@MohamedKALLEL首先在函数generate_particles中
coo [i] [0]代表x坐标,而coo i代表y坐标,只是看到generate_particles部分忘记了其余部分,它与您之前给我的相似,但是我用自己的语言和其他变量编写了它当我删除该文件时,在屏幕上绘制的坐标正是我要启动初始配置的坐标,但是在这里,我们要做的是将这些坐标写入配置二进制文件中,问题是当我读取此二进制文件时,似乎唯一打印的坐标是从0到n-1 n的层顺序,存在一个我无法解决的问题,也许是我编写代码的方式,因为我有547个粒子,但是此代码给出了我只有13个坐标,我应该给每个粒子一个标签,即547个粒子应该有自己的坐标,这很清楚吗?
最佳答案
int i, j;
float y,x;
float d=1.0;// d is the distance between 2 points as indicated in your schema
for(i=0; i<=(n-1); i++) {
y = (sqrt(3)*i*d)/2.0;
for (j = 0; j < (2*n-1-i); j++) {
x = (-(2*n-i-2)*d)/2.0 + j*d;
//plot the point with coordinate (x,y) here
if (y!=0) {
// plot the point with coordinate (x,-y) here
}
}
}
模式说明:
如您的Wikipedia链接中所示http://en.wikipedia.org/wiki/Centered_hexagonal_number以
nth
居中的六边形数字由以下公式给出关于c++ - 生成二维魔术六边形晶格的算法,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/14280831/