javascript - GreaseMonkey脚本，不解析添加到DOM的链接

我正在使用油脂猴子脚本，即Youtube Already：

该脚本旨在突出显示已访问的链接。关键因素是要去除使a：visited无效的url参数。

i.e.: http://www.youtube.com/watch?v=aKWPht3fU-o               !=
      http://www.youtube.com/watch?v=aKWPht3fU-o&featured=fvw

重要的部分是：

var cleanlink, dirtylink, i, x, aXpath;
aXpath = new Array(7);
aXpath[0] = '//a[contains(@href, "feature=related")]';
aXpath[1] = '//a[contains(@href, "feature=relmfu")]';
aXpath[2] = '//a[contains(@href, "feature=g-")]';
aXpath[3] = '//a[contains(@href, "feature=b-")]'; // &feature=b- all browse
aXpath[4] = '//a[contains(@href, "/user/")]';
aXpath[5] = '//a[contains(@href, "/videos")]';    // search
aXpath[6] = '//a[contains(@href, "&list")]';      // playlists

for(x in aXpath) {
    dirtylink = document.evaluate(aXpath[x], document, null, XPathResult.UNORDERED_NODE_SNAPSHOT_TYPE, null);
    for (i = 0; i < dirtylink.snapshotLength; i++) {
        cleanlink = dirtylink.snapshotItem(i);
        switch (x){
        case 6:
                    cleanlink.href = cleanlink.href.replace(/\&feature(.*)/,"").replace(/\&index(.*)/,"");
            break;
        case 4:
        case 5:
            cleanlink.href = cleanlink.href.replace(/\?(.*)/,"");

            break;
        default :
            cleanlink.href = cleanlink.href.replace(/\&(.*)/,"");
                }
    }
}

问题在于此代码将仅检查标准HTML youtube页面中的链接。随AJAX添加的链接（通常在youtube频道上）将不规范。

即使使用注入了AJAX的链接，该方法也可以运行此用户脚本吗？

最佳答案

除非您要为“规范化器”运行超时，否则没有直接的方法

setInterval(function() {
    //> code here
},1000);