python - 用`1.代替`1`。

假设这样的清单

l = ['1\xa0My Cll to Adventure: 1949–1967',
 '2\xa0Crossing the Threshold: 1967–1979',
 '3\xa0My Abyss: 1979–1982',
 '4\xa0My Rod of Trils: 1983–1994',
 '5\xa0The Ultimte Boon: 1995–21',
 '6\xa0Returning the Boon: 211–215',
 '7\xa0My Lst Yer nd My Gretest Chllenge: 216–217',
 '8\xa0Looking Bck from  Higher Level']

我想要的结果是

[' 1.My Cll to Adventure: 1949–1967',
 ' 2.Crossing the Threshold: 1967–1979',
 ' 3.My Abyss: 1979–1982',
 ' 4.My Rod of Trils: 1983–1994',
 ' 5.The Ultimte Boon: 1995–21',
 ' 6.Returning the Boon: 211–215',
 ' 7.My Lst Yer nd My Gretest Chllenge: 216–217',
 ' 8.Looking Bck from  Higher Level']

我尝试过代码

import re
In [114]: [re.sub(r'\d\xa0', r' \d.', i) for i in l]
Out[114]:
[' \\d.My Cll to Adventure: 1949–1967',
 ' \\d.Crossing the Threshold: 1967–1979',
 ' \\d.My Abyss: 1979–1982',
 ' \\d.My Rod of Trils: 1983–1994',
 ' \\d.The Ultimte Boon: 1995–21',
 ' \\d.Returning the Boon: 211–215',
 ' \\d.My Lst Yer nd My Gretest Chllenge: 216–217',
 ' \\d.Looking Bck from  Higher Level']

它未能按我的意图替换为数字。

如何完成这样的任务？

最佳答案

您没有在句号之前捕获所需的数字。为此，我们只需要在要捕获的数字周围使用括号，然后使用其捕获组ID（1）对其进行引用。

带有：

l = ['1\xa0My Cll to Adventure: 1949–1967',
 '2\xa0Crossing the Threshold: 1967–1979',
 '3\xa0My Abyss: 1979–1982',
 '4\xa0My Rod of Trils: 1983–1994',
 '5\xa0The Ultimte Boon: 1995–21',
 '6\xa0Returning the Boon: 211–215',
 '7\xa0My Lst Yer nd My Gretest Chllenge: 216–217',
 '8\xa0Looking Bck from  Higher Level']

然后我们运行：

import re
[re.sub(r'(\d+)\xa0', r' \1.', i) for i in l]

并获得输出：

[' 1.My Cll to Adventure: 1949–1967',
 ' 2.Crossing the Threshold: 1967–1979',
 ' 3.My Abyss: 1979–1982',
 ' 4.My Rod of Trils: 1983–1994',
 ' 5.The Ultimte Boon: 1995–21',
 ' 6.Returning the Boon: 211–215',
 ' 7.My Lst Yer nd My Gretest Chllenge: 216–217',
 ' 8.Looking Bck from  Higher Level']

关于python - 用`1.代替`1`。，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/48180363/