我正在尝试使用BroadcastReceiver来获取Internet连接状态。
接收器类是这样的:
public class ConnectivityReceiver extends BroadcastReceiver {
WebView mWebView;
@Override
public void onReceive(Context context, Intent intent) {
String action = intent.getAction();
Log.d(MSResearch.LOG_TAG, "Connectivity action: " + intent.getAction());
if (action.equals(WifiManager.WIFI_STATE_CHANGED_ACTION)) {
WifiManager wm = (WifiManager) context.getSystemService(Context.WIFI_SERVICE);
Log.e(MSResearch.LOG_TAG, "Setting wifistate: " + wm.getWifiState());
} else if (action.equals(ConnectivityManager.CONNECTIVITY_ACTION)) {
NetworkInfo ni = intent.getParcelableExtra (ConnectivityManager.EXTRA_NETWORK_INFO);
Log.e(MSResearch.LOG_TAG, "Setting isConnected: " + ni.isConnected());
}
}
}
我在onCreate()函数中实例化了Receive,并尝试在Activity类的onResume()中注册接收者,并在onPause()中取消注册。
public onCreate(){
...
conReceiver = new ConnectivityReceiver();
itFilter = new IntentFilter(ConnectivityManager.CONNECTIVITY_ACTION);
itFilter.addAction(WifiManager.WIFI_STATE_CHANGED_ACTION);
...
}
@Override
public void onResume(){
registerReceiver(conReceiver,itFilter);
}
@Override
public void onPause(){
unregisterReceiver(conReceiver);
}
我在onResume调用后就收到运行时异常。谁能告诉我我做错了什么?我什至尝试只在清单xml文件中添加接收者标签,而不是在活动中注册,但是我仍然遇到运行时异常。我已经在2.2和2.3模拟器上进行了尝试,但遇到了同样的问题。
Thread [<1> main] (Suspended (exception RuntimeException))
ActivityThread.performResumeActivity(IBinder, boolean) line: 3128
ActivityThread.handleResumeActivity(IBinder, boolean, boolean) line: 3143
ActivityThread.handleLaunchActivity(ActivityThread$ActivityRecord, Intent) line: 2684
ActivityThread.access$2300(ActivityThread, ActivityThread$ActivityRecord, Intent) line: 125
ActivityThread$H.handleMessage(Message) line: 2033
ActivityThread$H(Handler).dispatchMessage(Message) line: 99
Looper.loop() line: 123
ActivityThread.main(String[]) line: 4627
Method.invokeNative(Object, Object[], Class, Class[], Class, int, boolean) line: not available [native method]
Method.invoke(Object, Object...) line: 521
ZygoteInit$MethodAndArgsCaller.run() line: 868
ZygoteInit.main(String[]) line: 626
NativeStart.main(String[]) line: not available [native method]
最佳答案
我在连接到服务时遇到了类似的问题,并且由于在绑定完成之前进行了远程调用而引发了错误。
我建议您在调用registerReceiver之前检查所有对象是否已初始化。