是否有可能使FormView在刚通过其InsertItemTemplate插入的记录上自动默认为ReadOnly模式?看来这应该是FormView应该自然而然的事情。
最佳答案
是的,有可能。
我正在用Employee表演示它
使用以下Sql Server脚本创建名为的员工表tbemployee
CREATE TABLE [dbo].[tbemployee](
[empid] [int] IDENTITY(1,1) NOT NULL,
[ename] [varchar](50) NULL,
[eadd] [varchar](50) NULL,
[esal] [int] NULL,
[edno] [int] NULL,
CONSTRAINT [PK_tbemployee] PRIMARY KEY CLUSTERED
(
[empid] ASC
)
) ON [PRIMARY]
GO
下面显示了将记录插入FormView的源代码:
FormView.aspx
<asp:FormView ID="FormView1" runat="server" DataKeyNames="empid"
oniteminserting="FormView1_ItemInserting" DefaultMode="Insert"
onmodechanging="FormView1_ModeChanging">
<InsertItemTemplate>
ename:
<asp:TextBox ID="txtename" runat="server" Text='<%# Bind("ename") %>' />
<br />
eadd:
<asp:TextBox ID="txteadd" runat="server" Text='<%# Bind("eadd") %>' />
<br />
esal:
<asp:TextBox ID="txtesal" runat="server" Text='<%# Bind("esal") %>' />
<br />
edno:
<asp:TextBox ID="txtedno" runat="server" Text='<%# Bind("edno") %>' />
<br />
<asp:LinkButton ID="InsertButton" runat="server" CausesValidation="True"
CommandName="Insert" Text="Insert" />
<asp:LinkButton ID="InsertCancelButton" runat="server"
CausesValidation="False" CommandName="Cancel" Text="Cancel" />
</InsertItemTemplate>
<ItemTemplate>
empid:
<asp:Label ID="empidLabel" runat="server" Text='<%# Eval("empid") %>' />
<br />
ename:
<asp:Label ID="enameLabel" runat="server" Text='<%# Bind("ename") %>' />
<br />
eadd:
<asp:Label ID="eaddLabel" runat="server" Text='<%# Bind("eadd") %>' />
<br />
esal:
<asp:Label ID="esalLabel" runat="server" Text='<%# Bind("esal") %>' />
<br />
edno:
<asp:Label ID="ednoLabel" runat="server" Text='<%# Bind("edno") %>' />
<br />
<asp:LinkButton ID="NewButton" runat="server" CausesValidation="False"
CommandName="New" Text="New" />
</ItemTemplate>
</asp:FormView>
<asp:SqlDataSource ID="SqlDataSource1" runat="server"
ConnectionString="Data Source=gts7;Initial Catalog=dbemp14;Integrated Security=True;Pooling=False"
ProviderName="System.Data.SqlClient">
</asp:SqlDataSource>
并在FormView.aspx页面的“代码背后”中粘贴以下代码:
FormView.aspx.cs
using System;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Data;
using System.Data.SqlClient;
using System.Configuration;
public partial class _Default : System.Web.UI.Page
{
SqlConnection con=new SqlConnection(ConfigurationManager.ConnectionStrings["cn"].ConnectionString);
protected void Page_Load(object sender, EventArgs e)
{
}
protected void FormView1_ItemInserting(object sender, FormViewInsertEventArgs e)
{
string ename, eadd,insertqry;
Int32 esal, edno;
ename = ((TextBox)(FormView1.FindControl("txtename"))).Text;
eadd = ((TextBox)(FormView1.FindControl("txtename"))).Text;
esal = Convert.ToInt32(((TextBox)(FormView1.FindControl("txtesal"))).Text);
edno = Convert.ToInt32(((TextBox)(FormView1.FindControl("txtedno"))).Text);
insertqry="insert tbemployee(ename,eadd,esal,edno) values(@ename,@eadd,@esal,@edno)";
if (con.State == ConnectionState.Closed)
{
con.Open();
}
SqlCommand cmd = new SqlCommand(insertqry, con);
cmd.Parameters.Add("@ename", SqlDbType.VarChar, 50).Value = ename;
cmd.Parameters.Add("@eadd", SqlDbType.VarChar, 50).Value = eadd;
cmd.Parameters.Add("@esal", SqlDbType.Int).Value = esal;
cmd.Parameters.Add("@edno", SqlDbType.Int).Value = edno;
cmd.ExecuteNonQuery();
cmd.Dispose();
con.Close();
FormView1.ChangeMode(FormViewMode.ReadOnly);
formbind();
}
public void formbind()
{
if (FormView1.AllowPaging == true)
{
SqlDataAdapter adp = new SqlDataAdapter("select * from tbemployee", con);
DataSet ds = new DataSet();
adp.Fill(ds);
Int32 totrecords = ds.Tables[0].Rows.Count;
Int32 currentpageindex = totrecords - 1;
FormView1.PageIndex = currentpageindex;
FormView1.DataSource = ds;
FormView1.DataBind();
}
else
{
SqlDataAdapter adp = new SqlDataAdapter("select * from tbemployee where empid in (select isnull(max(empid),0) from tbemployee)", con);
DataSet ds = new DataSet();
adp.Fill(ds);
FormView1.DataSource = ds;
FormView1.DataBind();
}
}
protected void FormView1_ModeChanging(object sender, FormViewModeEventArgs e)
{
FormView1.ChangeMode(e.NewMode);
formbind();
}
关于asp.net - 自动将ASP.NET FormView绑定(bind)到新插入的记录,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/2218043/