我在上传图片时遇到了一些问题。我想从表中存储和检索图像,但是当我尝试获取图像时,它没有显示。只有损坏的图像图标。但是,如果我通过phpmyadmin手动上传图像,它将显示该图像。我的表格行的类型是blob。我很困惑。谁能帮忙。

我的代码很简单:

$pdo = new PDO('mysql:dbname=database_name;host=localhost', 'username', 'password',
                array(PDO::MYSQL_ATTR_INIT_COMMAND => 'SET NAMES utf8'));

              $imageName = mysql_real_escape_string($_FILES["image"]["name"]);
              $imageData = addslashes(file_get_contents($_FILES["image"]["tmp_name"]));
              $imageType = mysql_real_escape_string($_FILES["image"]["type"]);

              $stmt = $pdo->prepare('INSERT INTO image (name,image) VALUES (:name,:image)');
              $stmt->execute(array('name' => $imageName, 'image' => $imageData));
              echo "Image Uploaded";


              $res = mysql_query("SELECT * FROM image ");
              while ($row = mysql_fetch_assoc($res))
              {
                echo "<img src=data:image/jpeg;base64," . (base64_encode(($row['image']))) . " style='width:60px;height:60px;'>";
              }

最佳答案

尝试删除验证,您使用准备好的语句,不需要它。

              $pdo = new PDO('mysql:dbname=database_name;host=localhost', 'username', 'password',
                array(PDO::MYSQL_ATTR_INIT_COMMAND => 'SET NAMES utf8'));

              $imageName = $_FILES["image"]["name"];
              $imageData = file_get_contents($_FILES["image"]["tmp_name"]);
              $imageType = $_FILES["image"]["type"];

              $stmt = $pdo->prepare('INSERT INTO image (name,image) VALUES (:name,:image)');
              $stmt->execute(array('name' => $imageName, 'image' => $imageData));
              echo "Image Uploaded";


              $res = mysql_query("SELECT * FROM image ");
              while ($row = mysql_fetch_assoc($res))
              {
                echo "<img src=data:image/jpeg;base64," . (base64_encode(($row['image']))) . " style='width:60px;height:60px;'>";
              }

关于php - 使用PDO上传图片的麻烦,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/23168296/

10-13 00:49