string - 如何将UnsafePointer <CUnsignedChar>转换为String？

我试过这种方法：

String.stringWithCString(cString: UnsafePointer<CChar>, encoding: NSStringEncoding)

但不幸的是，它只适用于UnsafePointer<CChar>。我不知道如何把UnsafePointer<CUnsignedChar>转换成UnsafePointer<CChar>。

最佳答案

struct UnsafePointer<T>有一个构造函数，它接受不同
键入作为参数：

/// Convert from a UnsafePointer of a different type.
///
/// This is a fundamentally unsafe conversion.
init<U>(_ from: UnsafePointer<U>)

因此，您可以从ptr : UnsafePointer<CUnsignedChar>
具有

let str = String.stringWithCString(UnsafePointer(ptr), encoding: someEncoding)

或者，在UTF-8编码的情况下，使用

let str = String.fromCString(UnsafePointer(ptr))

注意，泛型类型<CChar>是从这里的上下文自动推断出来的，
即最后一行等于

let str = String.fromCString(UnsafePointer<CChar>(ptr))

关于string - 如何将UnsafePointer <CUnsignedChar>转换为String？，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/25850477/