有没有办法挂载仅包含特定于快照文件的虚拟分区?我知道隐藏的zfs目录,但其中包含快照时的所有文件。
我的目标是使差异备份更快。

提前致谢

格雷格

最佳答案

尽管安德鲁(Andrew)提出的zfs send是使用差异快照的正确方法,但是如果您只想查看差异并在您自己的脚本中或在没有ZFS支持的其他平台上使用差异,则还有zfs diff

zfs diff [-FHt] snapshot snapshot|filesystem

Display the difference between a snapshot of a given filesystem
and another snapshot of that filesystem from a later time or
the current contents of the filesystem.  The first column is a
character indicating the type of change, the other columns
indicate pathname, new pathname (in case of rename), change in
link count, and optionally file type and/or change time.

The types of change are:
  -       The path has been removed
  +       The path has been created
  M       The path has been modified
  R       The path has been renamed

-F
    Display an indication of the type of file, in a manner
    similar to the -F option of ls(1).
      B       Block device
      C       Character device
      /       Directory
      >       Door
      |       Named pipe
      @       Symbolic link
      P       Event port
      =       Socket
      F       Regular file
-H
    Give more parsable tab-separated output, without header
    lines and without arrows.
-t
    Display the path's inode change time as the first column of
    output.


请注意,两个数据集的顺序必须是时间顺序的。您可以解析结果列表,并且仅使用您感兴趣的那些文件名。

手册页中的示例输出:

# zfs diff -F tank/test@before tank/test
M       /       /tank/test/
M       F       /tank/test/linked      (+1)
R       F       /tank/test/oldname -> /tank/test/newname
-       F       /tank/test/deleted
+       F       /tank/test/created
M       F       /tank/test/modified


此外,如果使用Oracle Solaris 11.3,则还具有-r开关以递归方式比较所有子数据集。

关于zfs - 访问“仅差异” ZFS快照,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/35623511/

10-13 08:39