有没有办法挂载仅包含特定于快照文件的虚拟分区?我知道隐藏的zfs目录,但其中包含快照时的所有文件。
我的目标是使差异备份更快。
提前致谢
格雷格
最佳答案
尽管安德鲁(Andrew)提出的zfs send
是使用差异快照的正确方法,但是如果您只想查看差异并在您自己的脚本中或在没有ZFS支持的其他平台上使用差异,则还有zfs diff
:
zfs diff [-FHt] snapshot snapshot|filesystem
Display the difference between a snapshot of a given filesystem
and another snapshot of that filesystem from a later time or
the current contents of the filesystem. The first column is a
character indicating the type of change, the other columns
indicate pathname, new pathname (in case of rename), change in
link count, and optionally file type and/or change time.
The types of change are:
- The path has been removed
+ The path has been created
M The path has been modified
R The path has been renamed
-F
Display an indication of the type of file, in a manner
similar to the -F option of ls(1).
B Block device
C Character device
/ Directory
> Door
| Named pipe
@ Symbolic link
P Event port
= Socket
F Regular file
-H
Give more parsable tab-separated output, without header
lines and without arrows.
-t
Display the path's inode change time as the first column of
output.
请注意,两个数据集的顺序必须是时间顺序的。您可以解析结果列表,并且仅使用您感兴趣的那些文件名。
手册页中的示例输出:
# zfs diff -F tank/test@before tank/test
M / /tank/test/
M F /tank/test/linked (+1)
R F /tank/test/oldname -> /tank/test/newname
- F /tank/test/deleted
+ F /tank/test/created
M F /tank/test/modified
此外,如果使用Oracle Solaris 11.3,则还具有
-r
开关以递归方式比较所有子数据集。关于zfs - 访问“仅差异” ZFS快照,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/35623511/