这个问题已经在这里有了答案:
已关闭10年。
我有二十一点游戏的纸牌类,其中包含以下枚举:
enum Rank { Ace, Two, Three, Four, Five, Six, Seven, Eight, Nine, Ten, Jack, Queen, King };
enum Suit { Clubs, Diamonds, Hearts, Spades };
当我创建套牌时,我想编写如下代码:
// foreach Suit in Card::Suit
// foreach Rank in Card::Rank
// add new card(rank, suit) to deck
我相信C++中没有foreach。但是,如何遍历枚举?
谢谢,
斯宾塞
最佳答案
通常可以在enum
中添加元素以简化此操作:
enum Rank {
Ace, Two, Three, Four, Five, Six, Seven, Eight, Nine, Ten, Jack, Queen, King,
RankFirst = Ace, RankLast = King
};
enum Suit {
Clubs, Diamonds, Hearts, Spades,
SuitFirst = Clubs, SuitLast = Spades
};
然后,您可以将循环编写为:
for (int r = RankFirst; r <= RankLast; ++r) {
for (int s = SuitFirst; s <= SuitLast; ++s) {
deck.add(Card((Rank)r, (Suit)s));
}
}
关于foreach中的C++枚举,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/2941890/