我试图了解退出范围时析构函数调用的顺序。假设我有以下代码:
class Parent{
Parent(){cout<<"parent c called \n";}
~Parent(){cout<< "parent d called \n";}
};
class Child: public parent{
Child(){cout<< "child c called \n";}
~Child(){cout<<"child d called\n";}
};
现在，我知道子构造函数和析构函数是从父类派生的，因此以下主要内容:
int main(){
Parent Man;
Child Boy;
return 0;
}
将产生输出:
parent c called
parent c called
child c called
... //Now what?
但是现在，当我超出范围时会发生什么？我有很多东西需要销毁，那么编译器如何选择顺序？我可以有两种输出可能性:
parent c called | parent c called
parent c called | parent c called
child c called | child c called
child d called | parent d called
parent d called | child d called
parent d called | parent d called
如果首先破坏了Boy，则适用左例，如果首先破坏Man，则适用右例。计算机如何确定先删除哪一个？
最佳答案
派生的析构函数在祖先的析构函数之前被调用。因此，将首先调用Child析构函数主体，然后再调用Parent析构函数主体。并且构造的对象以相反的顺序被破坏，因此Boy对象将在Man对象被破坏之前被破坏。