StringBuilder result = new StringBuilder();
HttpServletResponse resp = (HttpServletResponse)response;
int status = 0;
BufferedReader rd=null;
CloseableHttpResponse closeableResponse = callApi(request);
status= closeableResponse.getStatusLine().getStatusCode();
logger.info("Response Code : {}", status);
try(
rd = new BufferedReader(
new InputStreamReader(closeableResponse.getEntity().getContent()))
){
String line = "";
while ((line = rd.readLine()) != null) {
result.append(line);
}
} finally{
if (rd!=null) rd.close();
}
我在下面的行中得到预期的标识符:
rd =新的BufferedReader(
新的InputStreamReader(closeableResponse.getEntity()。getContent()))
)
有什么想法吗?我已经定义了所有变量。为什么会出现此错误?
最佳答案
使用try-with-resources要求您在try部分中声明变量。
像这样:
try(BufferedReader rd = getBufferedReader()){
dfadl
}catch(IOException e){
dsfsd
}
关于java - Java 8:预期<identifier>,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/56697304/