我有以下格式的数据:
[['Director', 9010],
['Director - Product Manager', 9894],
['Director - Product Manager - Project Manager', 9080],
['Director - Product Manager - Project Manager - Staff', 5090],
['Director - Product Manager - Project Manager - Staff 2', 5087],
['Director - Product Manager - Project Manager 2', 9099],...]
并想要一个看起来像这样的输出:
{
'title': 'Director',
'id': 9010,
'children': [
{
'title': 'Product Manager',
'id': 9894,
'children': [
{
'title': 'Project Manager',
'id': 9080,
'children': [
...
]
},{
'title': 'Project Manager 2',
'id': 9099,
'children': [
...
]
}],
...
]
},
...
]
}
我一直在玩字典,但很难将 ID 与标题相匹配。任何建议表示赞赏。
最佳答案
一种有效的方法是使最外层成为列表而不是字典。当我们遍历标题字符串中的每个标题时,我们会在当前列表中查找具有该标题的字典。如果当前列表中不存在标题,那么我们需要创建一个新的字典。如果它确实存在,那么我们将该字典的子列表作为新的当前列表并继续寻找下一个标题。
我还编写了一个递归 prune
函数,一旦我们完成输入所有数据,它就会删除所有空的子列表,以防万一。
import json
lst = [
['Director', 9010],
['Director - Product Manager', 9894],
['Director - Product Manager - Project Manager', 9080],
['Director - Product Manager - Project Manager - Staff', 5090],
['Director - Product Manager - Project Manager - Staff 2', 5087],
['Director - Product Manager - Project Manager 2', 9099],
]
# Search for a matching name in the current list.
# If it doesn't exist, create it.
def insert(lst, name, idnum):
for d in lst:
if d['title'] == name:
break
else:
d = {'title': name, 'id': idnum, 'children': []}
lst.append(d)
return d['children']
# Remove empty child lists
def prune(lst):
for d in lst:
if d['children']:
prune(d['children'])
else:
del d['children']
# Insert the data into the master list
master = []
for names, idnum in lst:
lst = master
for name in [s.strip() for s in names.split(' - ')]:
lst = insert(lst, name, idnum)
prune(master)
# Get the top level dict from the master list
data = master[0]
print(json.dumps(data, indent=4))
输出
{
"title": "Director",
"id": 9010,
"children": [
{
"title": "Product Manager",
"id": 9894,
"children": [
{
"title": "Project Manager",
"id": 9080,
"children": [
{
"title": "Staff",
"id": 5090
},
{
"title": "Staff 2",
"id": 5087
}
]
},
{
"title": "Project Manager 2",
"id": 9099
}
]
}
]
}
关于python - 使用 Python 将分隔的字符串和值转换为分层 JSON,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/47153543/