我正在寻找从XML检索Body元素的值。虽然由于某种原因我正确地编写了代码，但我却得到了NULL指针异常。
package com.company;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathExpression;
import javax.xml.xpath.XPathExpressionException;
import javax.xml.xpath.XPathFactory;
import org.w3c.dom.DOMException;
import org.w3c.dom.Document;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;
import java.io.File;
import java.io.IOException;
import java.io.StringBufferInputStream;
import java.io.StringReader;
public class Main {
public static void main(String[] args) {
String xmlDoc = "<?xml version=\"1.0\" encoding=\"UTF-8\"?><Body>This is my content</Body>";
try {
DocumentBuilderFactory documentBuilderFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder documentBuilder = documentBuilderFactory.newDocumentBuilder();
Document document = documentBuilder.parse(new InputSource(new StringReader(xmlDoc)));
XPath xPath = XPathFactory.newInstance().newXPath();
XPathExpression expression = xPath.compile("/Body");
Node node = (Node) expression.evaluate(document, XPathConstants.NODE);
System.out.println("Body: " + node.getAttributes().getNamedItem("Body").getNodeValue());
}
catch (ParserConfigurationException | SAXException | IOException | DOMException | XPathExpressionException exp)
{
exp.printStackTrace();
}
}
}
最佳答案
尝试这个 ：）
String xmlDoc = "<?xml version=\"1.0\" encoding=\"UTF-8\"?><Body>This is my content</Body>";
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
String value = builder.parse(new InputSource(new ByteArrayInputStream(xmlDoc.getBytes())))
.getDocumentElement().getTextContent();
它在
<Body>标记内返回值-“这是我的内容”。