我使用此代码从XML文件获取页面标题。现在,我想显示对应标题的描述,该描述也出现在同一XML文件中。我怎么做?
var queryObj = new Object();
var querystring = location.search.replace('?', '');
var vars = querystring.split("&");
for (var i = 0; i < vars.length; i++)
{
var pair = vars[i].split('=');
var key = pair[0];
var value = pair[1];
var value = decodeURI(value);
queryObj[key] = value;
}
if(queryObj["activity"] != "" && queryObj["phase"] != "")
{
$("#TaskTitle").html(queryObj['phase']+": "+queryObj['activity']);
}
最佳答案
考虑我有这样的XML:
<?xml version="1.0"?>
<catalog>
<book id="bk101">
<author>Gambardella, Matthew</author>
<title>XML Developer's Guide</title>
<genre>Computer</genre>
<price>44.95</price>
<publish_date>2000-10-01</publish_date>
<description>An in-depth look at creating applications
with XML.</description>
</book>
<book id="bk102">
<author>Ralls, Kim</author>
<title>Midnight Rain</title>
<genre>Fantasy</genre>
<price>5.95</price>
<publish_date>2000-12-16</publish_date>
<description>A former architect battles corporate zombies,
an evil sorceress, and her own childhood to become queen
of the world.</description>
</book> ..so on
</catalog>
我将其存储在字符串中,然后在其上运行
parseXML()
,将其放入这样的变量中:var xmlDoc= $.parseXML(myXmlString)
我现在可以将此
xmlDoc
变量用作DOM对象,并在需要时通过将其传递给$()
作为参数遍历它。$(xmlDoc)
现在,您可以阅读
find()
,closest()
等内容,并学习如何在jQuery中遍历。例如,如果我想获得书籍XML开发人员指南的作者,该指南位于ID为
<book>
的#bk101
部分中,则可以这样做:$(xmlDoc).find("#bk101").find("author")
//OR
$(xmlDoc).find("#bk101 author")
//OR
$("#bk101", xmlDoc).find("author")
而已。这是一个演示:http://jsfiddle.net/hungerpain/N3mYa/