我想对我的HABTM属性做一个条件
我在CakePHP 2.x中具有以下HABTM关系:
Practise.php
public $hasAndBelongsToMany = array(
'Attribute' => array(
'className' => 'Attribute',
'joinTable' => 'practises_attributes',
'foreignKey' => 'practise_id',
'associationForeignKey' => 'attribute_id',
'unique' => true,
'conditions' => '',
'fields' => '',
'order' => '',
'limit' => '',
'offset' => '',
'finderQuery' => '',
)
);
Attribute.php
public $hasAndBelongsToMany = array(
'Practise' => array(
'className' => 'Practise',
'joinTable' => 'practises_attributes',
'foreignKey' => 'attribute_id',
'associationForeignKey' => 'practise_id',
'unique' => true,
'conditions' => '',
'fields' => '',
'order' => '',
'limit' => '',
'offset' => '',
'finderQuery' => '',
)
);
现在,我想在我的PractiseController.php中找到所有包含属性条件的条件
PractiseController.php
$cond['Attribute.id'] = array(1,2,3);
$this->Practise->find('all', array('conditions' => $cond));
然后我得到以下错误:
错误:SQLSTATE [42S22]:找不到列:1054“ where子句”中的未知列“ Attribute.id”
SQL查询:
选择
Practise
。id
,Practise
。title
,Practise
。body
,从
db
。practises
AS Practise
在
Attribute
。id
IN(1、2、3)中如何使CakePHP也可以将HABTM表加入查找查询中?
最佳答案
您可以使用包含为例
$this->Practise->find('all', array('contain' => 'Attribute.id = whatever'));
您也可以手动加入:
$options['joins'] = array(
array('table' => 'practises_attributes',
'alias' => 'PractiseAttribute',
'type' => 'INNER',
'conditions' => array(
'Attribute.id = whatever',
)
) );