以下程序:
using System;
using Newtonsoft.Json;
namespace JsonPlayground
{
public class Program
{
private struct Message
{
public string Value { get; }
[JsonConstructor]
public Message(string value)
{
if (value == null) throw new ArgumentNullException(nameof(value));
Value = value;
}
}
private class ObjectWithOptionalMessage
{
public Message? Message { get; }
public ObjectWithOptionalMessage(Message? message)
{
Message = message;
}
}
public static void Main(string[] args)
{
var objWithMessage = new ObjectWithOptionalMessage(new Message("Hello!"));
var serializerSettings = new JsonSerializerSettings
{
TypeNameHandling = TypeNameHandling.Auto,
Formatting = Formatting.Indented
};
Console.WriteLine(JsonConvert.SerializeObject(objWithMessage, serializerSettings));
}
}
}
给我以下输出:
{
"Message": {
"$type": "System.Nullable`1[[JsonPlayground.Program+Message, JsonPlayground]], System.Private.CoreLib",
"Value": "Hello!"
}
}
而且我想不出为什么要为明确声明的属性包含
$type
的原因。如果我声明Message
属性不可为空,则不包括$type
属性。我究竟做错了什么?
最佳答案
David G的评论成功了,是将其表达为答案,并应用JsonPropertyAttribute
,如下所示:
private class ObjectWithOptionalMessage
{
[JsonProperty(TypeNameHandling = TypeNameHandling.None)]
public Message? Message { get; }
public ObjectWithOptionalMessage(Message? message)
{
Message = message;
}
}
确实为我解决了问题。
关于c# - 可为空的结构和TypeNameHandling.Auto的JSON.NET序列化,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/40108477/