。a包含元素，我想知道b中匹配元素的索引。在a中，每个元素都是唯一的，不像在b中。
a = [1993, 1993, 1994, 1995, 1996, 1996, 1998, 2003, 2005, 2005]
b = [1966, 1967, 1968, 1969, 1970, 1971, 1972, 1973, 1974, 1975, 1976, 1977, 1978, 1979, 1980, 1981, 1982, 1983, 1984, 1985, 1986, 1987, 1988, 1989, 1990, 1991, 1992, 1993, 1994, 1995, 1996, 1997, 1998, 1999, 2000, 2001, 2002, 2003, 2004, 2005, 2006, 2007, 2008, 2009, 2010, 2011, 2012, 2013, 2014]
使用Finding the indices of matching elements in list in Python中的溶液：
matching = [match for match, element in enumerate(b) if element in a]
不过，它只是
b，但我希望它是a。 最佳答案
>>> a = [1993, 1993, 1994, 1995, 1996, 1996, 1998, 2003, 2005, 2005]
>>> b = [1966, 1967, 1968, 1969, 1970, 1971, 1972, 1973, 1974, 1975, 1976, 1977, 1978, 1979, 1980, 1981, 1982, 1983, 1984, 1985, 1986, 1987, 1988, 1989, 1990, 1991, 1992, 1993, 1994, 1995, 1996, 1997, 1998, 1999, 2000, 2001, 2002, 2003, 2004, 2005, 2006, 2007, 2008, 2009, 2010, 2011, 2012, 2013, 2014]
>>> [b.index(x) for x in a]
[27, 27, 28, 29, 30, 30, 32, 37, 39, 39]