我试图向使用Eve作为框架的Rest API发出POST请求,但是每当我尝试发布JSON时,都会收到422错误,提示无法处理的实体。我的GET请求工作正常。这是我的Eve应用程序的架构:
schema = {
'_update': {
'type': 'datetime',
'minlength': 1,
'maxlength': 40,
'required': False,
'unique': True,
},
'Name': {
'type': 'string',
'minlength': 1,
'maxlength': 40,
'required': True,
'unique': False,
},
'FacebookId': {
'type': 'integer',
'minlength': 1,
'maxlength': 40,
'required': True,
'unique': True,
},
'HighScore': {
'type': 'integer',
'minlength': 1,
'maxlength': 40,
'required': True,
'unique': False,
},
}
这是我要发布的JSON:
{"_updated":null,"Name":"John Doe","FacebookId":"12453523434324123","HighScore":15}
这是我尝试从客户端发出POST请求的方式:
IDictionary dict = Facebook.MiniJSON.Json.Deserialize(result.RawResult) as IDictionary;
string name = dict["name"].ToString();
string id = dict["id"].ToString();
Player player = new Player();
player.FacebookId = id;
player.Name = name;
player.HighScore = (int) GameManager.Instance.Points;
// Using Newtonsoft.Json to serialize
var json = JsonConvert.SerializeObject(player);
var headers = new Dictionary<string, string> {{"Content-Type", "application/json"}};
string url = "http://server.com/Players";
var encoding = new UTF8Encoding();
// Using Unity3d WWW class
WWW www = new WWW(url, encoding.GetBytes(json), headers);
StartCoroutine(WaitForRequest(www));
最佳答案
你让它变得如此复杂。首先,您需要一个帮助程序方法来调用您的服务。像这样的东西:
private static T Call<T>(string url, string body)
{
var contentBytes = Encoding.UTF8.GetBytes(body);
var request = (HttpWebRequest)WebRequest.Create(url);
request.Timeout = 60 * 1000;
request.ContentLength = contentBytes.Length;
request.Method = "POST";
request.ContentType = @"application/json";
using (var requestWritter = request.GetRequestStream())
requestWritter.Write(contentBytes, 0, (int)request.ContentLength);
var responseString = string.Empty;
var webResponse = (HttpWebResponse)request.GetResponse();
var responseStream = webResponse.GetResponseStream();
using (var reader = new StreamReader(responseStream))
responseString = reader.ReadToEnd();
return JsonConvert.DeserializeObject<T>(responseString);
}
然后简单地这样称呼它:
var url = "http://server.com/Players";
var output=Call<youroutputtype>(url, json);
注意:我不知道您的输出类型是什么,所以我留给您。