我有这样的对象,我需要用jmespath评估哪个是“最便宜的”
{
"wines": [
{
"name": "b",
"price1": 30,
"price2": 110
},
{
"name": "a",
"price1": 50,
"price2": 1
},
{
"name": "c",
"price1": 40,
"price2": 1130
}
]
}
输出应为:“ a”对象
我在做:
min_by(wines, &price1, &price2).name
min_by(wines, &price1).name
min_by(wines, sum(&price1, &price2)).name
但没有运气
最佳答案
根据您最便宜的意思,如果您要选择价格最低的价格与价格最低的价格相结合的商品,可以使用:min_by(wines, &sum([price1,price2]))
:
$ echo '{
"wines": [
{
"name": "b",
"price1": 30,
"price2": 110
},
{
"name": "a",
"price1": 50,
"price2": 1
},
{
"name": "c",
"price1": 40,
"price2": 1130
}
]
}' | jp 'min_by(wines, &sum([price1,price2]))'
{
"price2": 1,
"price1": 50,
"name": "a"
}
&
必须在第二个参数的开头,因为期望的类型是表达式引用。 &sum([price1,price2])
表示,对于wines
数组中的每个项目,计算表达式sum([price1,price2])
并使用结果值确定数组中的哪个项目是最小值。再举一个例子,如果您想在葡萄酒列表中选择价格最低的商品,即
price1
或price2
,则可以将sum
替换为min
:$ echo '{
"wines": [
{
"name": "b",
"price1": 30,
"price2": 110
},
{
"name": "a",
"price1": 50,
"price2": 1
},
{
"name": "c",
"price1": 40,
"price2": 1130
}
]
}' | jp 'min_by(wines, &min([price1,price2]))'
{
"price2": 1,
"price1": 50,
"name": "a"
}