json - 将两个json数组(加载到内存中)合并为一个json数组

我有两个json数组，我已经初始化如下。

local=[{"account_id":"01C","id":"0XVWKCFV6P9CA5"},{"account_id":"CSDTHQ","id":"631QGYBNSF"},...............]

org=[{"account_id":"BJPKWSH","id":"15BS0XP4F91V6YH4G0PV"},{"account_id":"01BKK44V5F6A1FKH60Q0ANX9JX","id":"01BKK44V7"},.....................]

我想要的是下面这样的东西。

outputJson=[{"account_id":"BJPKWSH","id":"15BS0XP4F91V6YH4G0PV"},
{"account_id":"BJPKWSH","id":"15BS0XP4F91V6YH4G0PV"},
{"account_id":"01BKK44V5F6A1FKH60Q0ANX9JX","id":"01BKK44V7"},.....................]

我想把这两个json数组合并成一个。
我试过了，

jq -s '.[0] * .[1]' <<< "$local $org"

但它给了parse error: Invalid literal at line 1, column 17

最佳答案

使用+，而不是*：

#!/bin/sh

j1='[{"account_id":"01C","id":"0XVWKCFV6P9CA5"},{"account_id":"CSDTHQ","id":"631QGYBNSF"}]'
j2='[{"account_id":"BJPKWSH","id":"15BS0XP4F91V6YH4G0PV"},{"account_id":"01BKK44V5F6A1FKH60Q0ANX9JX","id":"01BKK44V7"}]'
echo $(jq -s '.[0] + .[1]' <<EOF
$j1
$j2
EOF
)

生产：

[ { "account_id": "01C", "id": "0XVWKCFV6P9CA5" }, { "account_id": "CSDTHQ", "id": "631QGYBNSF" }, { "account_id": "BJPKWSH", "id": "15BS0XP4F91V6YH4G0PV" }, { "account_id": "01BKK44V5F6A1FKH60Q0ANX9JX", "id": "01BKK44V7" } ]