查询有问题。我试图从SturiType Type语言3的表中创建SELECT,或者如果SaveTyType ID ID分组,则不存在行(1)(如回退)。
+-----------------+--------------------------+-------------------+
| deposit_type_id | deposit_type_language_id | deposit_type_name |
+-----------------+--------------------------+-------------------+
| 1 | 1 | jewellery |
| 1 | 2 | bijuterii |
| 1 | 3 | šperky |
| 2 | 1 | equipment |
| 2 | 2 | tehnica |
+-----------------+--------------------------+-------------------+
我正在尝试以下查询:
SELECT t1.* from deposit_type AS t1
INNER JOIN
( SELECT deposit_type_id, min(deposit_type_language_id) from
deposit_type group by deposit_type_id ) AS t2
ON t1.deposit_type_id=t2.deposit_type_id group by deposit_type_id;
输出为:
+-----------------+--------------------------+-------------------+
| deposit_type_id | deposit_type_language_id | deposit_type_name |
+-----------------+--------------------------+-------------------+
| 1 | 1 | jewellery |
| 2 | 1 | equipment |
+-----------------+--------------------------+-------------------+
但我正在尝试实现如下目标:
+-----------------+--------------------------+-------------------+
| deposit_type_id | deposit_type_language_id | deposit_type_name |
+-----------------+--------------------------+-------------------+
| 1 | 3 | šperky |
| 2 | 1 | equipment |
+-----------------+--------------------------+-------------------+
我的错误在哪里?
表格结构:
deposit_type | CREATE TABLE `deposit_type` (
`deposit_type_id` smallint(5) unsigned NOT NULL,
`deposit_type_language_id` smallint(5) unsigned NOT NULL,
`deposit_type_name` varchar(96) NOT NULL,
PRIMARY KEY (`deposit_type_id`,`deposit_type_language_id`),
KEY `deposit_type_language_id` (`deposit_type_language_id`),
CONSTRAINT `deposit_type_ibfk_1` FOREIGN KEY (`deposit_type_language_id`) REFERENCES `language` (`language_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 |
最佳答案
憎恨者会憎恨。。。
SELECT x.deposit_type_id
, COALESCE(y.deposit_type_language_id,x.deposit_type_language_id) deposit_type_language_id
, COALESCE(y.deposit_type_name,x.deposit_type_name) deposit_type_name
FROM deposit_type x
LEFT
JOIN deposit_type y
ON y.deposit_type_id = x.deposit_type_id
AND y.deposit_type_language_id = 3
WHERE x.deposit_type_language_id = 1;
关于mysql - MySQL从具有回退的组中选择,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/33040772/