java - Java:如何使用相同算法对2 ArrayList进行洗牌？

我想用算法洗牌卡片列表和值列表，但是当我为每一个使用洗牌集合时，它们使用不同的算法所以当我从牌堆里抽出一张牌时，它将是一张随机牌，同一张牌不会再出现。

public class BlackJack {

    public static void main(String[] args) {
        Random rand = new Random();
        Scanner input =new Scanner(System.in);
        ArrayList<String> cardList= new ArrayList<String>();
        ArrayList<String> cardShuffle= new ArrayList<String>();
        ArrayList<Integer> valueList= new ArrayList<Integer>();
        ArrayList<String> valueShuffle= new ArrayList<String>();

        cardList = card(cardList);
        valueList = value(valueList);

        Collections.shuffle(cardList);
        Collections.shuffle(valueList);

        System.out.println(cardList);
        System.out.println(valueList);

    }
    private static ArrayList card(ArrayList<String> cardList){
        String cards = null;
        String suits = null;
        int cardCount = 0;
        for(int s = 1;s<5; s++){

            switch (s){
            case 1: suits = " of Heart"; break;
            case 2: suits = " of Diamond"; break;
            case 3: suits = " of Spades"; break;
            case 4: suits = " of Clubs"; break;
            }

            for(int c = 1;c<14; c++){
                switch (c){
                case 1: cards = "2"; break;
                case 2: cards = "3"; break;
                case 3: cards = "4"; break;
                case 4: cards = "5"; break;
                case 5: cards = "6"; break;
                case 6: cards = "7"; break;
                case 7: cards = "8"; break;
                case 8: cards = "9"; break;
                case 9: cards = "10"; break;
                case 10: cards = "Jack"; break;
                case 11: cards = "Queen"; break;
                case 12: cards = "King"; break;
                case 13: cards = "Ace"; break;
                }
                cardList.add(cardCount, cards + suits);
                cardCount++;
            }
        }

        return cardList;
    }
    private static ArrayList<Integer> value(ArrayList<Integer> valueList){

        int v = 2;
        int counter = 1;
        for(int c = 1;c<52; c++){
            if(v > 10){
                v = 10;
            }
            valueList.add(v);
            v++;
            counter++;
            if(counter>13){
                counter = 1;
                v=2;
            }
        }

        return valueList;
    }
}

编辑：我按照@桂皮的建议制作了第二个类，然后使用a For int随机数洗牌。

public class BlackJack {

    public static void main(String[] args) {
        Random rand = new Random();
        Scanner input =new Scanner(System.in);

        ArrayList<String> cardList= Cards.card();
        ArrayList<Integer> valueList= Cards.value();
        ArrayList<String> cardShuffle= new ArrayList<String>();
        ArrayList<Integer> valueShuffle= new ArrayList<Integer>();

        int r = 0;
         for(int i = 0; i < 52; i++){
             r = rand.nextInt(52);
                    cardShuffle.add(i,cardList.get(r));
                    valueShuffle.add(i,valueList.get(r));
             }
        System.out.println(cardShuffle);

}

最佳答案

我认为最好的解决方案是创建一个既能保存卡片又能保存价值的类：

class ValuedCard {

    private String card;
    private int value;

    // constructor, getters/setters...
}

然后你可以只有一个列表ArrayList<ValuedCard>并对其进行无序排列。

关于java - Java:如何使用相同算法对2 ArrayList进行洗牌？，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/32568916/