我有一个人的ID和他们的名字的列表,以及一个人的ID和他们的姓的列表。有些人没有名字,有些人没有姓;我想在两个列表上进行完全外部联接。
因此,以下列表:
ID FirstName
-- ---------
1 John
2 Sue
ID LastName
-- --------
1 Doe
3 Smith
应产生:
ID FirstName LastName
-- --------- --------
1 John Doe
2 Sue
3 Smith
我是LINQ的新手(如果我很la脚,请原谅我),并且已经找到了许多解决方案,这些解决方案看起来都非常相似,但实际上似乎是外部联接,而对于“LINQ外部联接”。
到目前为止,我的尝试是这样的:
private void OuterJoinTest()
{
List<FirstName> firstNames = new List<FirstName>();
firstNames.Add(new FirstName { ID = 1, Name = "John" });
firstNames.Add(new FirstName { ID = 2, Name = "Sue" });
List<LastName> lastNames = new List<LastName>();
lastNames.Add(new LastName { ID = 1, Name = "Doe" });
lastNames.Add(new LastName { ID = 3, Name = "Smith" });
var outerJoin = from first in firstNames
join last in lastNames
on first.ID equals last.ID
into temp
from last in temp.DefaultIfEmpty()
select new
{
id = first != null ? first.ID : last.ID,
firstname = first != null ? first.Name : string.Empty,
surname = last != null ? last.Name : string.Empty
};
}
}
public class FirstName
{
public int ID;
public string Name;
}
public class LastName
{
public int ID;
public string Name;
}
但这返回:
ID FirstName LastName
-- --------- --------
1 John Doe
2 Sue
我究竟做错了什么?
最佳答案
我不知道这是否涵盖所有情况,从逻辑上讲似乎是正确的。这个想法是采用左外部联接和右外部联接,然后取结果的并集。
var firstNames = new[]
{
new { ID = 1, Name = "John" },
new { ID = 2, Name = "Sue" },
};
var lastNames = new[]
{
new { ID = 1, Name = "Doe" },
new { ID = 3, Name = "Smith" },
};
var leftOuterJoin =
from first in firstNames
join last in lastNames on first.ID equals last.ID into temp
from last in temp.DefaultIfEmpty()
select new
{
first.ID,
FirstName = first.Name,
LastName = last?.Name,
};
var rightOuterJoin =
from last in lastNames
join first in firstNames on last.ID equals first.ID into temp
from first in temp.DefaultIfEmpty()
select new
{
last.ID,
FirstName = first?.Name,
LastName = last.Name,
};
var fullOuterJoin = leftOuterJoin.Union(rightOuterJoin);
由于它是在LINQ to Objects中编写的,因此按其编写的方式工作。如果是LINQ to SQL或其他,则查询处理器可能不支持安全导航或其他操作。您必须使用条件运算符有条件地获取值。
即
var leftOuterJoin =
from first in firstNames
join last in lastNames on first.ID equals last.ID into temp
from last in temp.DefaultIfEmpty()
select new
{
first.ID,
FirstName = first.Name,
LastName = last != null ? last.Name : default,
};