我正在尝试从数据库中选择所有行,其中display='Y'和announcement!=空。如何检查列以确保它包含值?
$qry = "select *
from school
where display='Y'
order by name, announcement, last_update";
最佳答案
$qry = "select *
from school
where display='Y'
and (announcement != '' AND announcement IS NOT null)
order by name, announcement, last_update";
这迎合了空白字段和空字段。
关于php - 如何检查MySQL列以确保其包含值?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/973649/