我正在尝试制作一个虚拟操纵杆,用户可以在C#中的WPF中用鼠标四处移动。我想使用极坐标系,因为我希望操纵杆的旋钮保持在圆中。
我得到一些非常奇怪的行为-如果有人对这种事情有经验,那么任何技巧都是不错的。谢谢
编辑:我得到它的工作。我在下面发布了更新的代码。这绝对不是一个好的/专业的解决方案,但它可以工作。因此,我希望将来有人尝试执行相同的任务可能会有所帮助。我试图添加一些注释来解释发生了什么。干得好!
注意:如果您要在程序中使用它,请注意必须更改两个硬编码值。第一个是x_starting / y_starting。多数民众赞成在您的虚拟操纵杆旋钮应重置为。其次是计算最大可能值时的半径。确保它是背景操纵杆宽度的一半。
代码:
using System;
using System.Collections.Generic;
using System.Diagnostics;
using System.Linq;
using System.Text;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;
using System.Windows.Documents;
using System.Windows.Input;
using System.Windows.Media;
using System.Windows.Media.Imaging;
using System.Windows.Navigation;
using System.Windows.Shapes;
namespace WpfApplication4
{
public partial class MainWindow : Window
{
public MainWindow()
{
InitializeComponent();
}
double radius;
bool captured = false;
double x_shape, x_canvas, y_shape, y_canvas; //Canvas is used to keep track of where the joystick is on screen,
// shape is used for where the knob is.
UIElement source = null;
double y_starting = 180; //The starting X and Y position for the Knob. (CHANGE TO WHERE UR CANVAS.TOP/CANVAS.LEFT IS FOR THE KNOB)
double x_starting = 105;
private void Ellipse_MouseLeftButtonDown(object sender, MouseButtonEventArgs e)
{
string objname = ((Ellipse)sender).Name;
if (objname == "Knob")
{
source = (UIElement)sender;
Mouse.Capture(source);
captured = true;
x_shape = Canvas.GetLeft(reference);
x_canvas = e.GetPosition(Knob).X;
y_shape = Canvas.GetTop(reference);
y_canvas = e.GetPosition(Knob).Y;
}
}
private void Ellipse_MouseLeftButtonUp(object sender, MouseButtonEventArgs e)
{
string objname = ((Ellipse)sender).Name;
Mouse.Capture(null);
captured = false;
if (objname == "Knob") {
// x_shape = x_starting;
// y_shape = y_starting;
Canvas.SetLeft(source, x_starting);
Canvas.SetTop(source, y_starting); //Reset to our starting values
XTextBlock.Text = x_starting.ToString();
YTextBlock.Text = y_starting.ToString();
}
}
private void Ellipse_MouseMove(object sender, MouseEventArgs e)
{
double x = e.GetPosition(reference).X; //Getting mouse pos relative to the center of your joystick (I have an empty textblock there called reference)
double y = e.GetPosition(reference).Y;
double r = Math.Sqrt((x * x) + (y * y)); //Calculate radius..
XMousePos.Text = x.ToString();
YMousePos.Text = y.ToString();
string objname = ((Ellipse)sender).Name;
double theta = Math.Atan2(y, x); //Calculate theta..
Theta.Text = theta.ToString();
double x1 = (r * Math.Cos(theta)); //This converts polar coordinates to cartesian plane coordinates.
double y1 = (r * Math.Sin(theta));
XPolPos.Text = x1.ToString();
YPolPos.Text = y1.ToString();
double xmax = (62.5 * Math.Cos(theta)); //Calculate a max so that your knob stays within the circle. The radius value should be half the width of the
double ymax = (62.5 * Math.Sin(theta)); // background of your joystick.
X2PolPos.Text = xmax.ToString();
Y2PolPos.Text = ymax.ToString();
if (objname == "Knob") {
if (captured)
{
if ((((x1 > 0) && (x1 < xmax)) || ((x1 <= 0) && (x1 > xmax))) && (((y1 > 0) && (y1 < ymax)) || ((y1 <= 0) && (y1 > ymax)))) //Seems like bad way to do it. But this is how i check to see if knob is in bounds.
{
x = e.GetPosition(reference).X; //Get the values and calculate it again.
y = e.GetPosition(reference).Y;
r = Math.Sqrt((x * x) + (y * y));
theta = Math.Atan2(y, x);
x1 = (r * Math.Cos(theta));
y1 = (r * Math.Sin(theta));
x_shape += x1 - x_canvas; //Changing our values and moving the knob.
Canvas.SetLeft(source, x_shape);
x_canvas = x1;
y_shape += y1 - y_canvas;
Canvas.SetTop(source, y_shape);
y_canvas = y1;
XTextBlock.Text = x_shape.ToString();
YTextBlock.Text = y_shape.ToString();
}
}
}
}
}
}
而XAML以防万一:
<Window x:Class="WpfApplication4.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="MainWindow" Height="350" Width="525" MouseMove="Window_MouseMove" KeyDown="Window_KeyDown">
<Grid>
<Grid.ColumnDefinitions>
<ColumnDefinition Width="*"/>
<ColumnDefinition Width="*"/>
</Grid.ColumnDefinitions>
<StackPanel Orientation="Vertical">
<TextBlock Text="KNOB POSITION"/>
<TextBlock Name="XTextBlock"/>
<TextBlock Name="YTextBlock"/>
<TextBlock Text="MOUSE POSITION"/>
<TextBlock Name="XMousePos"/>
<TextBlock Name="YMousePos"/>
<TextBlock Text="POLAR COORDINATES"/>
<TextBlock Name="XPolPos"/>
<TextBlock Name="YPolPos"/>
</StackPanel>
<Canvas Name="LayoutRoot" Grid.Column="1">
<Ellipse Fill="#FFF4F4F5" Name ="Joystick" Height="125" Canvas.Left="51" Stroke="Black" Canvas.Top="128" Width="125" MouseLeftButtonDown="Ellipse_MouseLeftButtonDown" MouseLeftButtonUp="Ellipse_MouseLeftButtonUp" MouseMove="Ellipse_MouseMove"/>
<Ellipse Fill="#FFF4F4F5" Name="Knob" Height="15" Canvas.Left="105" Stroke="Black" Canvas.Top="180" Width="15" MouseLeftButtonDown="Ellipse_MouseLeftButtonDown" MouseLeftButtonUp="Ellipse_MouseLeftButtonUp" MouseMove="Ellipse_MouseMove"/>
</Canvas>
</Grid>
最佳答案
当我们谈论操纵杆时,polar coordinate system
似乎没有帮助。
我们需要的是X和Y的偏移量在[-1; 1]。我们可以很容易地通过知道字段(大)Radius
,已归档的Center point
和Mouse coordinates
来评估它。
这是它的工作方式(删除Ellipse_MouseMove
以外的所有事件)。成员m_vtJoystickPos
保持选定的Joystick
职位。
public partial class MainWindow : Window
{
public MainWindow()
{
InitializeComponent();
UpdateKnobPosition();
}
/// <summary>
/// Current joystick position
/// </summary>
Vector m_vtJoystickPos = new Vector();
private void Ellipse_MouseMove(object sender, MouseEventArgs e)
{
double fJoystickRadius = Joystick.Height * 0.5;
//Make coords related to the center
Vector vtJoystickPos = e.GetPosition(Joystick) -
new Point(fJoystickRadius, fJoystickRadius);
//Normalize coords
vtJoystickPos /= fJoystickRadius;
//Limit R [0; 1]
if (vtJoystickPos.Length > 1.0)
vtJoystickPos.Normalize();
XMousePos.Text = vtJoystickPos.X.ToString();
YMousePos.Text = vtJoystickPos.Y.ToString();
//Polar coord system
double fTheta = Math.Atan2(vtJoystickPos.Y, vtJoystickPos.X);
XPolPos.Text = fTheta.ToString(); //Angle
YPolPos.Text = vtJoystickPos.Length.ToString(); //Radius
if (e.LeftButton == MouseButtonState.Pressed)
{
m_vtJoystickPos = vtJoystickPos;
UpdateKnobPosition();
}
}
void UpdateKnobPosition()
{
double fJoystickRadius = Joystick.Height * 0.5;
double fKnobRadius = Knob.Width * 0.5;
Canvas.SetLeft(Knob, Canvas.GetLeft(Joystick) +
m_vtJoystickPos.X * fJoystickRadius + fJoystickRadius - fKnobRadius);
Canvas.SetTop(Knob, Canvas.GetTop(Joystick) +
m_vtJoystickPos.Y * fJoystickRadius + fJoystickRadius - fKnobRadius);
}
}
我还包括Polar CS评估(有评论)。 BTW Polar CS为(R,角度)。
XAML:
<Window x:Class="WpfApplication1.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:local="clr-namespace:WpfApplication1"
mc:Ignorable="d"
Title="MainWindow" Height="350" Width="525">
<Grid>
<Grid.ColumnDefinitions>
<ColumnDefinition Width="*"/>
<ColumnDefinition Width="*"/>
</Grid.ColumnDefinitions>
<StackPanel Orientation="Vertical">
<TextBlock Text="KNOB POSITION"/>
<TextBlock Name="XTextBlock"/>
<TextBlock Name="YTextBlock"/>
<TextBlock Text="MOUSE POSITION"/>
<TextBlock Name="XMousePos"/>
<TextBlock Name="YMousePos"/>
<TextBlock Text="POLAR COORDINATES"/>
<TextBlock Name="XPolPos"/>
<TextBlock Name="YPolPos"/>
</StackPanel>
<Canvas Name="LayoutRoot" Grid.Column="1">
<Ellipse Fill="#FFF4F4F5" Name ="Joystick" Height="125" Canvas.Left="51" Stroke="Black" Canvas.Top="127" Width="125" MouseMove="Ellipse_MouseMove"/>
<Ellipse Fill="#FFF4F4F5" Name="Knob" Height="16" Canvas.Left="106" Stroke="Black" Canvas.Top="182" Width="15" MouseMove="Ellipse_MouseMove"/>
</Canvas>
</Grid>
</Window>
关于c# - C#WPF-使用极坐标的虚拟操纵杆,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/37421431/