javascript - 通用JSON调用类别

var JsonClientPatientSearch = Titanium.Network.createHTTPClient();

    // API Url to call
    var url = GetAPIUrl() + "PatientSearch";
    JsonClientPatientSearch.open("POST", url);
    //setting Request Header
    JsonClientPatientSearch.setRequestHeader("Content-type", "application/json");
      JsonClientPatientSearch.send(PatientSearch(PatientSearchCriteria,Credentials,Header));

    JsonClientPatientSearch.onload = function(){

    };
    JsonClientPatientSearch.onerror = function(e){

    };

我的项目中有很多JSON调用，是否可以编写一个类并使用其实例进行JSON调用...只传递参数...

最佳答案

您可以创建对象实例并重用它们。您的代码如下所示：

var MyCall = function(url, onLoad, onError){
    // API Url to call
    this.url = GetAPIUrl() + url;
    this.onLoad = onLoad;
    this.onError = onError;
};
MyCall.prototype = {
    call: function(){
        var JsonClientPatientSearch = Titanium.Network.createHTTPClient();
        JsonClientPatientSearch.open("POST", this.url);
        //setting Request Header
        JsonClientPatientSearch.setRequestHeader("Content-type", "application/json");
        JsonClientPatientSearch.send(PatientSearch(PatientSearchCriteria,Credentials,Header));
        JsonClientPatientSearch.onload = this.onLoad;
        JsonClientPatientSearch.onerror = this.onError;

    }
};

// create callbacks
var myLoad = function(response){ /* do something with response */ },
    myError = function(error){ /* do something with error  */ };
// create instance
new MyCall("PatientSearch", myLoad, myError);
// do a call
MyCall.call();

您需要根据与其他全局对象一起使用的方式进行调整。但是希望这能给您正确的方向。