这是我的代码。...我正在获取NumberFormatException和idk whow解决它..新手,完全卡住了,真的需要帮助

public class AcccountArray {

    public static void main(String[] args)
    {
        //Scan the file and save account details to array
        File file = new File ("customers.txt");
        System.out.println("Path : " + file.getAbsolutePath());
        try{
                    Scanner scanner = new Scanner("customers.txt");
                    String[][] Account = new String[Integer.valueOf(scanner.nextLine())][3];

                    for(int i=0;i<Account.length;i++)
                    {
                        Account[i][0]=scanner.nextLine();
                        //System.out.println(Account[i][0]);
                        Account[i][1]=scanner.nextLine();
                        //System.out.println(Account[i][1]);
                        Account[i][2]=scanner.nextLine();
                        //System.out.println(Account[i][2]);
                    }
                    scanner.close();


错误:

java.lang.NumberFormatException: For input string: "customers.txt"
    at java.lang.NumberFormatException.forInputString(Unknown Source)
    at java.lang.Integer.parseInt(Unknown Source)
    at java.lang.Integer.valueOf(Unknown Source)
    at AcccountArray.main(AcccountArray.java:15)


。 15是

String[][] Account = new String[Integer.valueOf(scanner.nextLine())][3];

最佳答案

对接受ScannerFile使用构造函数,以使扫描程序实例不使用String源:

Scanner scanner = new Scanner(new File("customers.txt"));


由于您已经有了此参考,因此可以使用

Scanner scanner = new Scanner(file);

07-27 13:48