我有一个查询,返回相关的视频标题,从一个给定的视频,所以相同的流派,国家,出版日期等。
我想使用video_names
函数排除某些not in ()
。问题是,查询返回我要排除的视频,它们也首先在数组中排序。为什么会这样?
public function interval($month, $not, $limit) {
$this->not = array_unique($not);
$i = implode(',', $this->not);
echo $i;//prints: onajr,babyjem,posh
$query = '
select title, artists, published, views, video_name, yt_id, duration, play_start, genre, country from videos
where
published BETWEEN :published - INTERVAL :month MONTH AND :published + INTERVAL :month MONTH
and MATCH(country) AGAINST(:country IN boolean mode)
and MATCH(genre) AGAINST(:genre IN boolean mode)
and
video_name not in (" :i ")
ORDER BY RAND() limit :limit
';
$run_query = $this->pdo->prepare($query);
$run_query->bindValue(':published', $this->published);
$run_query->bindValue(':country', '+' . $this->data->country);
$run_query->bindValue(':genre', '+' . $this->data->genre);
$run_query->bindValue(':limit', $limit, PDO::PARAM_INT);
$run_query->bindValue(':month', $month, PDO::PARAM_INT);
$run_query->bindValue(':i', $i);
$run_query->execute();
$data = $run_query->fetchAll(PDO::FETCH_ASSOC);
print_r($data);
//contains all three of them onajr,babyjem,posh
}
最佳答案
可以创建参数和值的数组,如下所示:
$this->not = array_unique($not);
$i = array();
foreach( $this->not as $key => $val ) {
$i[':vid_' . $key] = $val;
}
将其绑定到查询:
' ..... video_name not in ('. implode(',', array_keys($i)) .') ....'
然后,绑定参数:
foreach( $i as $key => $val ) {
$run_query->bindValue($key, $val);
}